lists.openwall.net   lists  /  announce  owl-users  owl-dev  john-users  john-dev  passwdqc-users  yescrypt  popa3d-users  /  oss-security  kernel-hardening  musl  sabotage  tlsify  passwords  /  crypt-dev  xvendor  /  Bugtraq  Full-Disclosure  linux-kernel  linux-netdev  linux-ext4  linux-hardening  linux-cve-announce  PHC 
Open Source and information security mailing list archives
 
Hash Suite: Windows password security audit tool. GUI, reports in PDF.
[<prev] [next>] [<thread-prev] [thread-next>] [day] [month] [year] [list]
Message-Id: <20110714183014.8b15e9b9.kamezawa.hiroyu@jp.fujitsu.com>
Date:	Thu, 14 Jul 2011 18:30:14 +0900
From:	KAMEZAWA Hiroyuki <kamezawa.hiroyu@...fujitsu.com>
To:	Michal Hocko <mhocko@...e.cz>
Cc:	linux-mm@...ck.org, Balbir Singh <bsingharora@...il.com>,
	Daisuke Nishimura <nishimura@....nes.nec.co.jp>,
	linux-kernel@...r.kernel.org
Subject: Re: [PATCH 1/2] memcg: make oom_lock 0 and 1 based rather than
 coutner

On Thu, 14 Jul 2011 11:00:17 +0200
Michal Hocko <mhocko@...e.cz> wrote:

> On Thu 14-07-11 11:59:13, KAMEZAWA Hiroyuki wrote:
> > On Thu, 14 Jul 2011 10:02:59 +0900
> > KAMEZAWA Hiroyuki <kamezawa.hiroyu@...fujitsu.com> wrote:
> > 
> > > On Wed, 13 Jul 2011 13:05:49 +0200
> > > Michal Hocko <mhocko@...e.cz> wrote:
> [...]
> > > > This patch replaces the counter by a simple {un}lock semantic. We are
> > > > using only 0 and 1 to distinguish those two states.
> > > > As mem_cgroup_oom_{un}lock works on the hierarchy we have to make sure
> > > > that we cannot race with somebody else which is already guaranteed
> > > > because we call both functions with the mutex held. All other consumers
> > > > just read the value atomically for a single group which is sufficient
> > > > because we set the value atomically.
> > > > The other thing is that only that process which locked the oom will
> > > > unlock it once the OOM is handled.
> > > > 
> > > > Signed-off-by: Michal Hocko <mhocko@...e.cz>
> > > > ---
> > > >  mm/memcontrol.c |   24 +++++++++++++++++-------
> > > >  1 files changed, 17 insertions(+), 7 deletions(-)
> > > > 
> > > > diff --git a/mm/memcontrol.c b/mm/memcontrol.c
> > > > index e013b8e..f6c9ead 100644
> > > > --- a/mm/memcontrol.c
> > > > +++ b/mm/memcontrol.c
> > > > @@ -1803,22 +1803,31 @@ static int mem_cgroup_hierarchical_reclaim(struct mem_cgroup *root_mem,
> > > >  /*
> > > >   * Check OOM-Killer is already running under our hierarchy.
> > > >   * If someone is running, return false.
> > > > + * Has to be called with memcg_oom_mutex
> > > >   */
> > > >  static bool mem_cgroup_oom_lock(struct mem_cgroup *mem)
> > > >  {
> > > > -	int x, lock_count = 0;
> > > > +	int x, lock_count = -1;
> > > >  	struct mem_cgroup *iter;
> > > >  
> > > >  	for_each_mem_cgroup_tree(iter, mem) {
> > > > -		x = atomic_inc_return(&iter->oom_lock);
> > > > -		lock_count = max(x, lock_count);
> > > > +		x = !!atomic_add_unless(&iter->oom_lock, 1, 1);
> > > > +		if (lock_count == -1)
> > > > +			lock_count = x;
> > > > +
> > > 
> > > 
> > > Hmm...Assume following hierarchy.
> > > 
> > > 	  A
> > >        B     C
> > >       D E 
> 
> IIUC, A, B, D, E are one hierarchy, right?
> 
yes.


> > > 
> > > The orignal code hanldes the situation
> > > 
> > >  1. B-D-E is under OOM
> > >  2. A enters OOM after 1.
> > > 
> > > In original code, A will not invoke OOM (because B-D-E oom will kill a process.)
> > > The new code invokes A will invoke new OOM....right ?
> 
> Sorry, I do not understand what you mean by that. 

This is your code.
==
 	for_each_mem_cgroup_tree(iter, mem) {
-		x = atomic_inc_return(&iter->oom_lock);
-		lock_count = max(x, lock_count);
+		x = !!atomic_add_unless(&iter->oom_lock, 1, 1);
+		if (lock_count == -1)
+			lock_count = x;
+
+		/* New child can be created but we shouldn't race with
+		 * somebody else trying to oom because we are under
+		 * memcg_oom_mutex
+		 */
+		BUG_ON(lock_count != x);
 	}
==

When, B,D,E is under OOM,  

   A oom_lock = 0
   B oom_lock = 1
   C oom_lock = 0
   D oom_lock = 1
   E oom_lock = 1

Here, assume A enters OOM.

   A oom_lock = 1 -- (*)
   B oom_lock = 1
   C oom_lock = 1
   D oom_lock = 1
   E oom_lock = 1

because of (*), mem_cgroup_oom_lock() will return lock_count=1, true.

Then, a new oom-killer will another oom-kiiler running in B-D-E.




> The original code and
> the new code do the same in that regards they lock the whole hierarchy.
> The only difference is that the original one increments the counter for
> all groups in the hierarchy while the new one just sets it to from 0->1
> BUG_ON just checks that we are not racing with somebody else.
> 


In above situation, old code's result is

   A oom_lock = 1
   B oom_lock = 2
   C oom_lock = 1
   D oom_lock = 2
   E oom_lock = 2

Then, max lockcount== 2 and return value is false. 



> > > 
> > > I wonder this kind of code
> > > ==
> > > 	bool success = true;
> > > 	...
> > > 	for_each_mem_cgroup_tree(iter, mem) {
> > > 		success &= !!atomic_add_unless(&iter->oom_lock, 1, 1);
> > > 		/* "break" loop is not allowed because of css refcount....*/
> > > 	}
> > > 	return success.
> > > ==
> > > Then, one hierarchy can invoke one OOM kill within it.
> > > But this will not work because we can't do proper unlock.
> 
> Why cannot we do a proper unlock?
> 

After 1st lock by oom in B-D-E

   A oom_lock = 0
   B oom_lock = 1
   C oom_lock = 0
   D oom_lock = 1
   E oom_lock = 1

returns true. and mem_cgroup_oom_unlock() will scan B-D-E and set oom_lock==0.

2nd lock by oom in A-B-C-D-E

  A oom_lock = 1
  B oom_lock = 1
  C oom_lock = 1
  D oom_lock = 1
  E oom_lock = 1

returns false, then, mem_cgroup_oom_unlock() will not be called.

After unlock, we see

  A oom_lock = 1
  B oom_lock = 0
  C oom_lock = 1
  D oom_lock = 0
  E oom_lock = 0


> > > 
> > > 
> > > Hm. how about this ? This has only one lock point and we'll not see the BUG.
> > > Not tested yet..
> > > 
> > Here, tested patch + test program. this seems to work well.
> 
> Will look at it later. At first glance it looks rather complicated. But
> maybe I am missing something. I have to confess I am not absolutely sure
> when it comes to hierarchies.
> 


With my patch, oom_lock shows the lock owner memcg. oom status is divided to
the vairable, under_oom.

(1) At 1st vistor by oom in B-D-E

  A oom_lock = 0  under_oom=0
  B oom_lock = 1  under_oom=1
  C oom_lock = 0  under_oom=0
  D oom_lock = 0  under_oom=1
  E oom_lock - 0  under_oom=0

returns true.

(2) At 2nd visrot by oom in A-B-C-D-E

  A oom_lock = 1  under_oom=1
  B oom_lock = 0  under_oom=1
  C oom_lock = 0  under_oom=1
  D oom_lock = 0  under_oom=1
  E oom_lock = 0  under_oom=1

The lock moves to A and returns false.

(3) at unlock, the thread which did (1) will find group A and
    unlock all hierarchy.


  A oom_lock = 0  under_oom=0
  B oom_lock = 0  under_oom=0
  C oom_lock = 0  under_oom=0
  D oom_lock = 0  under_oom=0
  E oom_lock = 0  under_oom=0


Thanks,
-Kame








--
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to majordomo@...r.kernel.org
More majordomo info at  http://vger.kernel.org/majordomo-info.html
Please read the FAQ at  http://www.tux.org/lkml/

Powered by blists - more mailing lists

Powered by Openwall GNU/*/Linux Powered by OpenVZ