linux-kernel - Re: [PATCH 11/18] block: add bdi flag to indicate risk of io queue underrun

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Date:	Wed, 07 Sep 2011 09:31:09 +0200
From:	Peter Zijlstra <a.p.zijlstra@...llo.nl>
To:	Wu Fengguang <fengguang.wu@...el.com>
Cc:	"linux-fsdevel@...r.kernel.org" <linux-fsdevel@...r.kernel.org>,
	Tejun Heo <tj@...nel.org>, Jens Axboe <axboe@...nel.dk>,
	"Li, Shaohua" <shaohua.li@...el.com>,
	Andrew Morton <akpm@...ux-foundation.org>,
	Jan Kara <jack@...e.cz>, Christoph Hellwig <hch@....de>,
	Dave Chinner <david@...morbit.com>,
	Greg Thelen <gthelen@...gle.com>,
	Minchan Kim <minchan.kim@...il.com>,
	Vivek Goyal <vgoyal@...hat.com>,
	Andrea Righi <arighi@...eler.com>,
	linux-mm <linux-mm@...ck.org>,
	LKML <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH 11/18] block: add bdi flag to indicate risk of io queue
 underrun

On Wed, 2011-09-07 at 10:37 +0800, Wu Fengguang wrote:
> On Tue, Sep 06, 2011 at 10:22:48PM +0800, Peter Zijlstra wrote:
> > On Sun, 2011-09-04 at 09:53 +0800, Wu Fengguang wrote:
> > > +++ linux-next/mm/page-writeback.c      2011-08-31 14:40:58.000000000 +0800
> > > @@ -1067,6 +1067,9 @@ static void balance_dirty_pages(struct a
> > >                                      nr_dirty, bdi_thresh, bdi_dirty,
> > >                                      start_time);
> > >  
> > > +               if (unlikely(!dirty_exceeded && bdi_async_underrun(bdi)))
> > > +                       break;
> > > +
> > >                 dirty_ratelimit = bdi->dirty_ratelimit;
> > >                 pos_ratio = bdi_position_ratio(bdi, dirty_thresh,
> > >                                                background_thresh, nr_dirty,
> > 
> > So dirty_exceeded looks like:
> > 
> > 
> > 1109                 dirty_exceeded = (bdi_dirty > bdi_thresh) ||
> > 1110                                   (nr_dirty > dirty_thresh);
> > 
> > Would it make sense to write it as:
> > 
> > 	if (nr_dirty > dirty_thresh || 
> > 	    (nr_dirty > freerun && bdi_dirty > bdi_thresh))
> > 		dirty_exceeded = 1;
> > 
> > So that we don't actually throttle bdi thingies when we're still in the
> > freerun area?
> 
> Sounds not necessary -- (nr_dirty > freerun) is implicitly true
> because there is a big break early in the loop:
> 
>         if (nr_dirty > freerun)
>                 break;

Ah, totally didn't see that. Thanks!
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