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Message-ID: <20110913200658.GC2362@BohrerMBP.rgmadvisors.com>
Date:	Tue, 13 Sep 2011 15:06:58 -0500
From:	Shawn Bohrer <sbohrer@...advisors.com>
To:	Steven Rostedt <rostedt@...dmis.org>
Cc:	Ingo Molnar <mingo@...e.hu>, Peter Zijlstra <peterz@...radead.org>,
	linux-kernel@...r.kernel.org
Subject: Re: [PATCH] sched_rt: Migrate equal priority tasks to available CPUs

On Tue, Sep 13, 2011 at 11:27:14AM -0500, Shawn Bohrer wrote:
> On Tue, Sep 13, 2011 at 09:05:46AM -0400, Steven Rostedt wrote:
> > Looks good, but do you have a test case that shows the issue? I like to
> > have something that proves even the obvious before making changes to the
> > schedule.
>
> I played around a little this morning trying to make a simple test case
> that reproduces the issue, but so far I've been unsuccessful.  My simple
> test cases trying to simulate the workload above actually do get evenly
> distributed across all CPUs.  If I get some more time I'll see if I can
> get an example to trigger the issue, but feel free to see if you can
> reproduce it as well.

Alright, I'm still having trouble making a case that actually resulted
in some CPUs left completely idle while others are loaded, but the
rough test case below does still show the benefit of the patch.

$ gcc -o sched_rt_migration sched_rt_migration.c
$ chrt -f 1 ./sched_rt_migration &

# Run 5 times with 3.0
$ sudo trace-cmd record -e sched:sched_switch -e sched:sched_wakeup sleep 1
$ trace-cmd report -r -w -F 'sched: comm == "sched_rt_migrat" || next_comm == "sched_rt_migrat"' | tail -4

Wakeup Latency
Average: 2.551 usecs Max: 188.409 usecs
Average: 2.372 usecs Max: 187.185 usecs
Average: 2.559 usecs Max: 182.151 usecs
Average: 2.628 usecs Max: 180.113 usecs
Average: 2.559 usecs Max: 178.105 usecs

# Run 5 with 3.0 + patch

Wakeup Latency
Average: 0.730 usecs Max: 8.037 usecs
Average: 0.721 usecs Max: 16.613 usecs
Average: 0.718 usecs Max: 16.613 usecs
Average: 0.693 usecs Max: 58.095 usecs
Average: 0.703 usecs Max: 11.078 usecs

So you can see that the patch does decrease both the Average and the
max wakeup latency.



#include <sys/time.h>
#include <stdio.h>
#include <unistd.h>
#include <sys/syscall.h>
#include <time.h>
#include <sys/sysinfo.h>
#include <stdint.h>
#include <sys/timerfd.h>


#define WORKLOAD_HIGH 100000
#define WORKLOAD_LOW  100

void worker()
{
	int timerfd, ret;
	struct itimerspec new_value, old_value;

	timerfd = timerfd_create(CLOCK_MONOTONIC, 0);
	if (timerfd == -1) {
		perror("timerfd_create");
		return;
	}

	new_value.it_value.tv_sec = 0;
	new_value.it_value.tv_nsec = 250000;
	new_value.it_interval.tv_sec = 0;
	new_value.it_interval.tv_nsec = 250000;

	ret = timerfd_settime(timerfd, 0, &new_value, &old_value);
	if (ret == -1) {
		perror("timerfd_settime");
		return;
	}

	while (1) {
		int i, j, loops, event_count;
		uint64_t buf;
		for (i = 0; i < 10; ++i) {
			read(timerfd, &buf, sizeof(buf));

			if (i == 0)
				loops = WORKLOAD_HIGH;
			else
				loops = WORKLOAD_LOW;
			for (j = 0; j < loops; ++j)
				/* burn cpu */;
		}
	}
}


int main ()
{
	int i, nprocs;
	pid_t pid;


	nprocs = get_nprocs();
	for (i = 0; i < 2 * nprocs - 1; ++i) {
		pid = fork();
		if (pid == 0)
			worker();
		else if (pid == -1)
			perror("fork");
	}

	worker();
}


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