linux-kernel - Re: [PATCH 06/16] sched: SCHED

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Message-ID: <1334237738.23924.334.camel@gandalf.stny.rr.com>
Date:	Thu, 12 Apr 2012 09:35:38 -0400
From:	Steven Rostedt <rostedt@...dmis.org>
To:	Hillf Danton <dhillf@...il.com>
Cc:	Juri Lelli <juri.lelli@...il.com>, peterz@...radead.org,
	tglx@...utronix.de, mingo@...hat.com, cfriesen@...tel.com,
	oleg@...hat.com, fweisbec@...il.com, darren@...art.com,
	johan.eker@...csson.com, p.faure@...tech.ch,
	linux-kernel@...r.kernel.org, claudio@...dence.eu.com,
	michael@...rulasolutions.com, fcheccon@...per.es
Subject: Re: [PATCH 06/16] sched: SCHED_DEADLINE push and pull logic

On Thu, 2012-04-12 at 20:56 +0800, Hillf Danton wrote:

> >>       if (2 == dl_nr_migratory + dl_nr_total)
> >>               rq was not overloaded;
> >>
> >>       after enqueuing a deadline task that is not migratory,
> >
> > Now rq would be overloaded because:
> >
> >        dl_nr_migratory + dl_nr_total == 3
> >
> 
> Which is the current task, and where?

More riddles?

The current task is the one executing on the CPU.

-- Steve

> 
> >
> >>
> >>       if (current task is not preempted)
> >>               rq remains not overloaded;
> >
> > s/not//
> >
> >>
> >>       else if (current task is not pushed out) {
> >>               if (rq is not overloaded)
> >>                       maintenance of overloaded is __corrupted__;
> >>       }
> >>
> >> btw, same behavior in RTS?
> >
> > I still don't understand what you are saying.
> >
> > I can see your scenario happening with the change you are suggesting
> > though.
> >
> > -- Steve
> >
> >


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