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Message-ID: <4FBD1493.7000104@zytor.com>
Date: Wed, 23 May 2012 09:47:15 -0700
From: "H. Peter Anvin" <hpa@...or.com>
To: Linus Torvalds <torvalds@...ux-foundation.org>
CC: Peter Zijlstra <a.p.zijlstra@...llo.nl>,
Borislav Petkov <borislav.petkov@....com>, mingo@...nel.org,
linux-kernel@...r.kernel.org, frank.arnold@....com,
akpm@...ux-foundation.org, tglx@...utronix.de,
linux-tip-commits@...r.kernel.org
Subject: Re: [tip:x86/mce] x86/bitops: Move BIT_64() for a wider use
On 05/23/2012 09:43 AM, Linus Torvalds wrote:
> On Wed, May 23, 2012 at 9:31 AM, H. Peter Anvin <hpa@...or.com> wrote:
>>>>
>>>> And it should return UL for shift values < 32 and ULL otherwise.
>>>
>>
>> Why do you want that behavior? That seems bizarre...
>
> We *have* to have that behavior.
>
> A 64-bit value on a 32-bit architecture has fundamentally different
> semantics than a 32-bit one.
>
> It expands arithmetic, but it has other semantic differences too.
> Think "printf()" etc. We don't want to force people to do 64-bit
> arithmetic on x86-32 when they are working with BIT(0), for chrissake!
>
> So if people make BIT(0) be a 64-bit value on a 32-bit architecture,
> I'm going to run around naked with a chainsaw, and call people morons.
> That's just not acceptable.
>
BIT(0), okay. I thought we were talking about BIT_64() here...
Any reason we can't just tell people to use BIT() for a native "unsigned
long" type (32/64 bits) and BIT_64() if they really want a 64-bit result?
There are good reasons for the latter. Consider, for example:
u64 msr;
...
msr &= ~BIT_64(1);
This *better* not be an unsigned 32 bit value, or we just chopped off
the upper half. In this case and similar ones the 64-bitness of the
result really matters.
-hpa
--
H. Peter Anvin, Intel Open Source Technology Center
I work for Intel. I don't speak on their behalf.
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