linux-kernel - Re: [PATCH v6] hashtable: introduce a small and naive hashtable

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Date:	Thu, 27 Sep 2012 10:33:18 +0200
From:	Sasha Levin <levinsasha928@...il.com>
To:	David Laight <David.Laight@...LAB.COM>
CC:	Mathieu Desnoyers <mathieu.desnoyers@...icios.com>,
	Steven Rostedt <rostedt@...dmis.org>,
	torvalds@...ux-foundation.org, tj@...nel.org,
	akpm@...ux-foundation.org, linux-kernel@...r.kernel.org,
	ebiederm@...ssion.com, neilb@...e.de, bfields@...ldses.org,
	ejt@...hat.com, snitzer@...hat.com, edumazet@...gle.com,
	josh@...htriplett.org, rmallon@...il.com, palves@...hat.com
Subject: Re: [PATCH v6] hashtable: introduce a small and naive hashtable

On 09/27/2012 10:25 AM, David Laight wrote:
>>>> And even then, if we would do:
>>>>
>>>>  	for (i = 0; i < HASH_SIZE(hashtable); i++)
>>>>  		if (!hlist_empty(&hashtable[i]))
>>>>  			break;
>>>>
>>>>  	return i >= HASH_SIZE(hashtable);
>>>>
>>>> What happens if the last entry of the table is non-empty ?
>>>
>>> It still works, as 'i' is not incremented due to the break. And i will
>>> still be less than HASH_SIZE(hashtable). Did you have *your* cup of
>>> coffee today? ;-)
>>
>> Ahh, right! Actually I had it already ;-)
> 
> I tend to dislike the repeated test, gcc might be able to optimise
> it away, but the code is cleaner written as:
> 
> 	for (i = 0; i < HASH_SIZE(hashtable); i++)
> 		if (!hlist_empty(&hashtable[i]))
> 			return false;
> 	return true;

Right, the flag thing in the macro was there just to make it work properly as a macro.

>> Agreed that the flags should be removed. Moving to define + static
>> inline is still important though.
> 
> Not sure I'd bother making the function inline.

I usually never make anything 'inline', I just let gcc do it's own thing when it compiles the code. If there are any objections
please let me know before I send the new version.


Thanks,
Sasha

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