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Message-ID: <alpine.LFD.2.02.1210191020010.4221@tux.localdomain>
Date: Fri, 19 Oct 2012 10:20:32 +0300 (EEST)
From: Pekka Enberg <penberg@...nel.org>
To: Joonsoo Kim <js1304@...il.com>
cc: linux-kernel@...r.kernel.org, linux-mm@...ck.org,
Christoph Lameter <cl@...ux.com>
Subject: Re: [PATCH 2/2] slub: remove one code path and reduce lock contention
in __slab_free()
On Thu, 16 Aug 2012, Joonsoo Kim wrote:
> When we try to free object, there is some of case that we need
> to take a node lock. This is the necessary step for preventing a race.
> After taking a lock, then we try to cmpxchg_double_slab().
> But, there is a possible scenario that cmpxchg_double_slab() is failed
> with taking a lock. Following example explains it.
>
> CPU A CPU B
> need lock
> ... need lock
> ... lock!!
> lock..but spin free success
> spin... unlock
> lock!!
> free fail
>
> In this case, retry with taking a lock is occured in CPU A.
> I think that in this case for CPU A,
> "release a lock first, and re-take a lock if necessary" is preferable way.
>
> There are two reasons for this.
>
> First, this makes __slab_free()'s logic somehow simple.
> With this patch, 'was_frozen = 1' is "always" handled without taking a lock.
> So we can remove one code path.
>
> Second, it may reduce lock contention.
> When we do retrying, status of slab is already changed,
> so we don't need a lock anymore in almost every case.
> "release a lock first, and re-take a lock if necessary" policy is
> helpful to this.
>
> Signed-off-by: Joonsoo Kim <js1304@...il.com>
> Cc: Christoph Lameter <cl@...ux.com>
> Acked-by: Christoph Lameter <cl@...ux.com>
Applied, thanks!
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