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Message-ID: <CACxGe6tZOjMXR6CNDzDTSUkcERLiX-2+Qoad0bcPum5Z-Jxaaw@mail.gmail.com>
Date: Thu, 15 Nov 2012 18:20:36 +0000
From: Grant Likely <grant.likely@...retlab.ca>
To: Stephen Warren <swarren@...dotorg.org>
Cc: linux-arch@...r.kernel.org, linux-mips@...ux-mips.org,
Stephen Warren <swarren@...dia.com>,
devicetree-discuss@...ts.ozlabs.org, linux-kernel@...r.kernel.org,
Sam Ravnborg <sam@...nborg.org>
Subject: Re: [PATCH V5 1/2] kbuild: centralize .dts->.dtb rule
On Thu, Nov 15, 2012 at 6:09 PM, Stephen Warren <swarren@...dotorg.org> wrote:
> On 11/15/2012 04:51 AM, Grant Likely wrote:
>> Grant Likely wrote:
>>> Or how about: I could pick up the patch with only the MIPS hunk and
>>> every other user can be fixed up independently to use the new rule.
>>
>> Here's a trial patch to fix up ARM. Does this look correct? This patch
>> depends on the generic dtb build rule already being applied.
>
> I think the patch looks OK technically, except for one minor comment below.
>
> One issue with this patch is that it moves *.dts from arch/arm/boot to
> arch/arm/boot/dts, which means everyone has to adjust their scripts/...
> that package/install/... the kernel. I guess it's an easy change for
> people to make, but could easily catch people unawares if they do
> incremental builds so that arch/arm/boot/*.dtb still exists but is stale.
True. We could temporarily remove or rename if the same file exists in
the directory below to help people catch that problem. I really would
like to clean up that build rule to be consistent though.
The other option is to move all the .dts files into the boot
directory, but I don't think that is a good idea at all.
>> +targets += dtbs
>
> Doesn't that make the "dtbs" target always run by default? Perhaps
> that's reasonable though, and doesn't actually affect anything since the
> make command for this directory always specifies an explicit target?
>
> Or, was that meant to be the following that got removed from ../Makefile?
>
> targets += $(dtb-y)
Yes it is supposed to be the same thing. Doesn't it effectively do the
same since dtbs depends on $(dtb-y)?
g.
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