linux-kernel - Re: Why is the kfree() argument const?

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Message-ID: <50F35CD3.9080300@gmail.com>
Date:	Mon, 14 Jan 2013 09:18:11 +0800
From:	Chen Gang F T <chen.gang.flying.transformer@...il.com>
To:	Cong Ding <dinggnu@...il.com>
CC:	antoine.trux@...il.com, fa.linux.kernel@...glegroups.com,
	Johannes Weiner <hannes@...urebad.de>,
	Linux Kernel Mailing List <linux-kernel@...r.kernel.org>,
	clameter@....com, penberg@...helsinki.fi
Subject: Re: Why is the kfree() argument const?

于 2013年01月14日 04:54, Cong Ding 写道:
> On Sun, Jan 13, 2013 at 9:10 AM, Chen Gang F T
> <chen.gang.flying.transformer@...il.com> wrote:
>> >   all together:
>> >     kfree() should use 'const void *' as parameter type
>> >     the free() of C Library is incorrect (it use void *).
> you are definitely wrong. both of them are correct - it's the
> difference between kernel space and user space.
> 

  for API features, they are should be no different.

 "- From a very obvious and very *real* caller perspective, 'free()' really 
   doesn't change the thing the pointer points to. It does something 
   totally different: it makes the *pointer* itself invalid."

   "we want the types to be as tight as possible"

  so should use 'const void *' both for 'kfree()' and 'free()' .

-- 
Chen Gang

Flying Transformer

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