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Message-ID: <20130719002408.GB21367@linux.vnet.ibm.com>
Date: Thu, 18 Jul 2013 17:24:08 -0700
From: "Paul E. McKenney" <paulmck@...ux.vnet.ibm.com>
To: Frederic Weisbecker <fweisbec@...il.com>
Cc: linux-kernel@...r.kernel.org, mingo@...e.hu, laijs@...fujitsu.com,
dipankar@...ibm.com, akpm@...ux-foundation.org,
mathieu.desnoyers@...ymtl.ca, josh@...htriplett.org,
niv@...ibm.com, tglx@...utronix.de, peterz@...radead.org,
rostedt@...dmis.org, dhowells@...hat.com, edumazet@...gle.com,
darren@...art.com, sbw@....edu
Subject: Re: [PATCH RFC nohz_full 6/7] nohz_full: Add full-system-idle state
machine
On Fri, Jul 19, 2013 at 12:46:21AM +0200, Frederic Weisbecker wrote:
> On Thu, Jul 18, 2013 at 09:47:49AM -0700, Paul E. McKenney wrote:
> > On Thu, Jul 18, 2013 at 04:24:51PM +0200, Frederic Weisbecker wrote:
> > > On Wed, Jul 17, 2013 at 08:39:21PM -0700, Paul E. McKenney wrote:
> > > > On Thu, Jul 18, 2013 at 03:33:01AM +0200, Frederic Weisbecker wrote:
> > > > > So it's like:
> > > > >
> > > > > CPU 0 CPU 1
> > > > >
> > > > > read I write I
> > > > > smp_mb() smp_mb()
> > > > > cmpxchg S read S
> > > > >
> > > > > I still can't find what guarantees we don't read a value in CPU 1 that is way below
> > > > > what we want.
> > > >
> > > > One key point is that there is a second cycle from LONG to FULL.
> > > >
> > > > (Not saying that there is not a bug -- there might well be. In fact,
> > > > I am starting to think that I need to do another Promela model...
> > >
> > > Now I'm very confused :)
> >
> > To quote a Nobel Laureate who presented at an ISEF here in Portland some
> > years back, "Confusion is the most productive state of mind." ;-)
>
> Then I must be a very productive guy!
So that is your secret! ;-)
> > > I'm far from being a specialist on these matters but I would really love to
> > > understand this patchset. Is there any documentation somewhere I can read
> > > that could help, something about cycles of committed memory or something?
> >
> > Documentation/memory-barriers.txt should suffice for this. If you want
> > more rigor, http://www.cl.cam.ac.uk/~pes20/ppc-supplemental/test7.pdf
> >
> > But memory-barrier pairing suffices here. Here is case 2 from my
> > earlier email in more detail. The comments with capital letters
> > mark important memory barriers, some of which are buried in atomic
> > operations.
> >
> > 1. Some CPU coming out of idle:
> >
> > o rcu_sysidle_exit():
> >
> > smp_mb__before_atomic_inc();
> > atomic_inc(&rdtp->dynticks_idle);
> > smp_mb__after_atomic_inc(); /* A */
> >
> > o rcu_sysidle_force_exit():
> >
> > oldstate = ACCESS_ONCE(full_sysidle_state);
> >
> > 2. RCU GP kthread:
> >
> > o rcu_sysidle():
> >
> > cmpxchg(&full_sysidle_state, RCU_SYSIDLE_SHORT, RCU_SYSIDLE_LONG);
> > /* B */
> >
> > o rcu_sysidle_check_cpu():
> >
> > cur = atomic_read(&rdtp->dynticks_idle);
> >
> > Memory barrier A pairs with memory barrier B, so that if #1's load
> > from full_sysidle_state sees RCU_SYSIDLE_SHORT, we know that #1's
> > atomic_inc() must be visible to #2's atomic_read(). This will cause #2
> > to recognize that the CPU came out of idle, which will in turn cause it
> > to invoke rcu_sysidle_cancel() instead of rcu_sysidle(), resulting in
> > full_sysidle_state being set to RCU_SYSIDLE_NOT.
>
> Ok I get it for that direction.
> Now imagine CPU 0 is the RCU GP kthread (#2) and CPU 1 is idle and stays
> so.
>
> CPU 0 then rounds and see that all CPUs are idle, until it finally sets
> up RCU_SYSIDLE_SHORT_FULL and finally goes to sleep.
>
> Then CPU 1 wakes up. It really has to see a value above RCU_SYSIDLE_SHORT
> otherwise it won't do the cmpxchg and see the FULL_NOTED that makes it send
> the IPI.
>
> What provides the guarantee that CPU 1 sees a value above RCU_SYSIDLE_SHORT?
> Not on the cmpxchg but when it first dereference with ACCESS_ONCE.
The trick is that CPU 0 will have scanned, moved to RCU_SYSIDLE_SHORT,
scanned, moved to RCU_SYSIDLE_LONG, then scanned again before moving
to RCU_SYSIDLE_FULL. Given CPU 1 has been idle all this time, CPU 0
will have read its ->dynticks_idle counter on each scan and seen it
having an even value. When CPU 1 comes out of idle, it will atomically
increment its ->dyntick_idle(), which will happen after CPU 0's read of
->dyntick_idle() during its last scan.
Because of the memory-barrier pairing above, this means that CPU
1's read from full_sysidle_state must follow the cmpxchg() that
set full_sysidle_state to RCU_SYSIDLE_LONG (though not necessarily
the two later cmpxchg()s that set it to RCU_SYSIDLE_FULL and
RCU_SYSIDLE_FULL_NOTED). But because RCU_SYSIDLE_LONG is greater than
RCU_SYSIDLE_SHORT, CPU 1 will take action to end the idle period.
Thanx, Paul
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