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Message-ID: <20130827103422.GA17355@larmbr-lcx>
Date:	Tue, 27 Aug 2013 18:34:22 +0800
From:	larmbr <nasa4836@...il.com>
To:	linux-kernel@...r.kernel.org
Cc:	paulmck@...ux.vnet.ibm.com, dhowells@...hat.com, nasa4836@...il.com
Subject: [PATCH] Documentation/memory-barriers: fix a error that mistakes a
 CPU notion in Section Transitivity

The memory-barriers document may has a error in Section TRANSITIVITY.

For transitivity, see a example below, given that

* CPU 2's load from X follows CPU 1's store to X, and 
  CPU 2's load from Y preceds CPU 3's store to Y.


 CPU 1                   CPU 2                   CPU 3
 ======================= ======================= =======================
         { X = 0, Y = 0 }
 STORE X=1               LOAD X                  STORE Y=1
                         <read barrier>          <general barrier>
                         LOAD Y                  LOAD X

The <read barrier> in CPU 2 is inadquate, because it could _only_ guarantees
that load operation _happen before_ load operation after the barrier, with
respect to CPU 3, which constrained by a general barrier, but provide _NO_
guarantee that CPU 1' store X will happen before the <read barrier>.

Therefore, if this example runs on a system where CPUs 1 and 3 share a store buffer
or a level of cache, CPU 3 might have early access to CPU 1's writes.

The original text has mistaken CPU 2 for CPU 3, so this patch fixes this, and adds
a paragraph to explain why a <full barrier> should guarantee this.

Signed-off-by: Zhan Jianyu <nasa4836@...il.com>
---
Documentation/memory-barriers.txt |   11 +++++++++--
1 file changed, 9 insertions(+), 2 deletions(-)

diff --git a/Documentation/memory-barriers.txt b/Documentation/memory-barriers.txt
index fa5d8a9..590a5a9 100644
--- a/Documentation/memory-barriers.txt
+++ b/Documentation/memory-barriers.txt
@@ -992,6 +992,13 @@ transitivity.  Therefore, in the above example, if CPU 2's load from X
 returns 1 and its load from Y returns 0, then CPU 3's load from X must
 also return 1.
 
+The key point is that CPU 1's storing 1 to X preceds CPU 2's loading 1
+from X, and CPU 2's loading 0 from Y preceds CPU 3's storing 1 to Y,
+which implies a ordering that the general barrier in CPU 2 guarantees:
+all store and load operations must happen before those after the barrier
+with respect to view of CPU 3, which constrained by a general barrier, too.
+Thus, CPU 3's load from X must return 1.
+
 However, transitivity is -not- guaranteed for read or write barriers.
 For example, suppose that CPU 2's general barrier in the above example
 is changed to a read barrier as shown below:
@@ -1009,8 +1016,8 @@ and CPU 3's load from X to return 0.
 
 The key point is that although CPU 2's read barrier orders its pair
 of loads, it does not guarantee to order CPU 1's store.  Therefore, if
-this example runs on a system where CPUs 1 and 2 share a store buffer
-or a level of cache, CPU 2 might have early access to CPU 1's writes.
+this example runs on a system where CPUs 1 and 3 share a store buffer
+or a level of cache, CPU 3 might have early access to CPU 1's writes.
 General barriers are therefore required to ensure that all CPUs agree
 on the combined order of CPU 1's and CPU 2's accesses.
 
--
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