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Message-ID: <52F3D9A9.1070107@parallels.com>
Date:	Thu, 6 Feb 2014 22:51:21 +0400
From:	Vladimir Davydov <vdavydov@...allels.com>
To:	Andrew Morton <akpm@...ux-foundation.org>
CC:	<linux-kernel@...r.kernel.org>, <linux-mm@...ck.org>,
	<devel@...nvz.org>, Mel Gorman <mgorman@...e.de>,
	Michal Hocko <mhocko@...e.cz>,
	Johannes Weiner <hannes@...xchg.org>,
	Rik van Riel <riel@...hat.com>,
	Dave Chinner <dchinner@...hat.com>,
	Glauber Costa <glommer@...il.com>
Subject: Re: [PATCH 2/3] mm: vmscan: get rid of DEFAULT_SEEKS and document
 shrink_slab logic

On 02/06/2014 12:52 AM, Andrew Morton wrote:
> On Wed, 5 Feb 2014 11:16:49 +0400 Vladimir Davydov <vdavydov@...allels.com> wrote:
>
>>> So why did I originally make DEFAULT_SEEKS=2?  Because I figured that to
>>> recreate (say) an inode would require a seek to the inode data then a
>>> seek back.  Is it legitimate to include the
>>> seek-back-to-what-you-were-doing-before seek in the cost of an inode
>>> reclaim?  I guess so...
>> Hmm, that explains this 2. Since we typically don't need to "seek back"
>> when recreating a cache page, as they are usually read in bunches by
>> readahead, the number of seeks to bring back a user page is 1, while the
>> number of seeks to recreate an average inode is 2, right?
> Sounds right to me.
>
>> Then to scan inodes and user pages so that they would generate
>> approximately the same number of seeks, we should calculate the number
>> of objects to scan as follows:
>>
>> nr_objects_to_scan = nr_pages_scanned / lru_pages *
>>                                         nr_freeable_objects /
>> shrinker->seeks
>>
>> where shrinker->seeks = DEFAULT_SEEKS = 2 for inodes.
> hm, I wonder if we should take the size of the object into account. 
> Should we be maximizing (memory-reclaimed / seeks-to-reestablish-it).

I'm not sure I understand you quite right. You mean that if two slab
caches have obj sizes 1k and 2k and both of them need 2 seeks to
recreate an object, we should scan the 1k (or 2k?) slab cache more
aggressively than the 2k one? Hmm... I don't know. It depends on what we
want to achieve. But this won't balance the seeks, which is our goal for
now, IIUC.

>> But currently we
>> have four times that. I can explain why we should multiply this by 2 -
>> we do not count pages moving from active to inactive lrus in
>> nr_pages_scanned, and 2*nr_pages_scanned can be a good approximation for
>> that - but I have no idea why we multiply it by 4...
> I don't understand this code at all:
>
> 	total_scan = nr;
> 	delta = (4 * nr_pages_scanned) / shrinker->seeks;
> 	delta *= freeable;
> 	do_div(delta, lru_pages + 1);
> 	total_scan += delta;
>
> If it actually makes any sense, it sorely sorely needs documentation.

To find its roots I had to checkout the linux history tree:

commit c3f4656118a78c1c294e0b4d338ac946265a822b
Author: Andrew Morton <akpm@...l.org>
Date:   Mon Dec 29 23:48:44 2003 -0800

    [PATCH] shrink_slab acounts for seeks incorrectly
   
    wli points out that shrink_slab inverts the sense of
shrinker->seeks: those
    caches which require more seeks to reestablish an object are shrunk
harder.
    That's wrong - they should be shrunk less.
   
    So fix that up, but scaling the result so that the patch is actually
a no-op
    at this time, because all caches use DEFAULT_SEEKS (2).

diff --git a/mm/vmscan.c b/mm/vmscan.c
index b8594827bbac..f2da3c9fb346 100644
--- a/mm/vmscan.c
+++ b/mm/vmscan.c
@@ -154,7 +154,7 @@ static int shrink_slab(long scanned, unsigned int
gfp_mask)
        list_for_each_entry(shrinker, &shrinker_list, list) {
                unsigned long long delta;
 
-               delta = scanned * shrinker->seeks;
+               delta = 4 * (scanned / shrinker->seeks);
                delta *= (*shrinker->shrinker)(0, gfp_mask);
                do_div(delta, pages + 1);
                shrinker->nr += delta;


So the idea seemed to be fixing a bug without introducing any functional
changes. Since then we have been living with this "4", which makes no
sense (?). Nobody complained though.

Thanks.

> David, you touched it last.  Any hints?

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