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Message-ID: <20140301005047.GA14777@linux.vnet.ibm.com>
Date: Fri, 28 Feb 2014 16:50:48 -0800
From: "Paul E. McKenney" <paulmck@...ux.vnet.ibm.com>
To: Linus Torvalds <torvalds@...ux-foundation.org>
Cc: Torvald Riegel <triegel@...hat.com>,
Will Deacon <will.deacon@....com>,
Peter Zijlstra <peterz@...radead.org>,
Ramana Radhakrishnan <Ramana.Radhakrishnan@....com>,
David Howells <dhowells@...hat.com>,
"linux-arch@...r.kernel.org" <linux-arch@...r.kernel.org>,
"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
"akpm@...ux-foundation.org" <akpm@...ux-foundation.org>,
"mingo@...nel.org" <mingo@...nel.org>,
"gcc@....gnu.org" <gcc@....gnu.org>
Subject: Re: [RFC][PATCH 0/5] arch: atomic rework
On Thu, Feb 27, 2014 at 12:53:12PM -0800, Paul E. McKenney wrote:
> On Thu, Feb 27, 2014 at 11:47:08AM -0800, Linus Torvalds wrote:
> > On Thu, Feb 27, 2014 at 11:06 AM, Paul E. McKenney
> > <paulmck@...ux.vnet.ibm.com> wrote:
> > >
> > > 3. The comparison was against another RCU-protected pointer,
> > > where that other pointer was properly fetched using one
> > > of the RCU primitives. Here it doesn't matter which pointer
> > > you use. At least as long as the rcu_assign_pointer() for
> > > that other pointer happened after the last update to the
> > > pointed-to structure.
> > >
> > > I am a bit nervous about #3. Any thoughts on it?
> >
> > I think that it might be worth pointing out as an example, and saying
> > that code like
> >
> > p = atomic_read(consume);
> > X;
> > q = atomic_read(consume);
> > Y;
> > if (p == q)
> > data = p->val;
> >
> > then the access of "p->val" is constrained to be data-dependent on
> > *either* p or q, but you can't really tell which, since the compiler
> > can decide that the values are interchangeable.
> >
> > I cannot for the life of me come up with a situation where this would
> > matter, though. If "X" contains a fence, then that fence will be a
> > stronger ordering than anything the consume through "p" would
> > guarantee anyway. And if "X" does *not* contain a fence, then the
> > atomic reads of p and q are unordered *anyway*, so then whether the
> > ordering to the access through "p" is through p or q is kind of
> > irrelevant. No?
>
> I can make a contrived litmus test for it, but you are right, the only
> time you can see it happen is when X has no barriers, in which case
> you don't have any ordering anyway -- both the compiler and the CPU can
> reorder the loads into p and q, and the read from p->val can, as you say,
> come from either pointer.
>
> For whatever it is worth, hear is the litmus test:
>
> T1: p = kmalloc(...);
> if (p == NULL)
> deal_with_it();
> p->a = 42; /* Each field in its own cache line. */
> p->b = 43;
> p->c = 44;
> atomic_store_explicit(&gp1, p, memory_order_release);
> p->b = 143;
> p->c = 144;
> atomic_store_explicit(&gp2, p, memory_order_release);
>
> T2: p = atomic_load_explicit(&gp2, memory_order_consume);
> r1 = p->b; /* Guaranteed to get 143. */
> q = atomic_load_explicit(&gp1, memory_order_consume);
> if (p == q) {
> /* The compiler decides that q->c is same as p->c. */
> r2 = p->c; /* Could get 44 on weakly order system. */
> }
>
> The loads from gp1 and gp2 are, as you say, unordered, so you get what
> you get.
>
> And publishing a structure via one RCU-protected pointer, updating it,
> then publishing it via another pointer seems to me to be asking for
> trouble anyway. If you really want to do something like that and still
> see consistency across all the fields in the structure, please put a lock
> in the structure and use it to guard updates and accesses to those fields.
And here is a patch documenting the restrictions for the current Linux
kernel. The rules change a bit due to rcu_dereference() acting a bit
differently than atomic_load_explicit(&p, memory_order_consume).
Thoughts?
Thanx, Paul
------------------------------------------------------------------------
documentation: Record rcu_dereference() value mishandling
Recent LKML discussings (see http://lwn.net/Articles/586838/ and
http://lwn.net/Articles/588300/ for the LWN writeups) brought out
some ways of misusing the return value from rcu_dereference() that
are not necessarily completely intuitive. This commit therefore
documents what can and cannot safely be done with these values.
Signed-off-by: Paul E. McKenney <paulmck@...ux.vnet.ibm.com>
diff --git a/Documentation/RCU/00-INDEX b/Documentation/RCU/00-INDEX
index fa57139f50bf..f773a264ae02 100644
--- a/Documentation/RCU/00-INDEX
+++ b/Documentation/RCU/00-INDEX
@@ -12,6 +12,8 @@ lockdep-splat.txt
- RCU Lockdep splats explained.
NMI-RCU.txt
- Using RCU to Protect Dynamic NMI Handlers
+rcu_dereference.txt
+ - Proper care and feeding of return values from rcu_dereference()
rcubarrier.txt
- RCU and Unloadable Modules
rculist_nulls.txt
diff --git a/Documentation/RCU/checklist.txt b/Documentation/RCU/checklist.txt
index 9d10d1db16a5..877947130ebe 100644
--- a/Documentation/RCU/checklist.txt
+++ b/Documentation/RCU/checklist.txt
@@ -114,12 +114,16 @@ over a rather long period of time, but improvements are always welcome!
http://www.openvms.compaq.com/wizard/wiz_2637.html
The rcu_dereference() primitive is also an excellent
- documentation aid, letting the person reading the code
- know exactly which pointers are protected by RCU.
+ documentation aid, letting the person reading the
+ code know exactly which pointers are protected by RCU.
Please note that compilers can also reorder code, and
they are becoming increasingly aggressive about doing
- just that. The rcu_dereference() primitive therefore
- also prevents destructive compiler optimizations.
+ just that. The rcu_dereference() primitive therefore also
+ prevents destructive compiler optimizations. However,
+ with a bit of devious creativity, it is possible to
+ mishandle the return value from rcu_dereference().
+ Please see rcu_dereference.txt in this directory for
+ more information.
The rcu_dereference() primitive is used by the
various "_rcu()" list-traversal primitives, such
diff --git a/Documentation/RCU/rcu_dereference.txt b/Documentation/RCU/rcu_dereference.txt
new file mode 100644
index 000000000000..6e72cd8622df
--- /dev/null
+++ b/Documentation/RCU/rcu_dereference.txt
@@ -0,0 +1,365 @@
+PROPER CARE AND FEEDING OF RETURN VALUES FROM rcu_dereference()
+
+Most of the time, you can use values from rcu_dereference() or one of
+the similar primitives without worries. Dereferencing (prefix "*"),
+field selection ("->"), assignment ("="), address-of ("&"), addition and
+subtraction of constants, and casts all work quite naturally and safely.
+
+It is nevertheless possible to get into trouble with other operations.
+Follow these rules to keep your RCU code working properly:
+
+o You must use one of the rcu_dereference() family of primitives
+ to load an RCU-protected pointer, otherwise CONFIG_PROVE_RCU
+ will complain. Worse yet, your code can see random memory-corruption
+ bugs due to games that compilers and DEC Alpha can play.
+ Without one of the rcu_dereference() primitives, compilers
+ can reload the value, and won't your code have fun with two
+ different values for a single pointer! Without rcu_dereference(),
+ DEC Alpha can load a pointer, dereference that pointer, and
+ return data preceding initialization that preceded the store of
+ the pointer.
+
+ In addition, the volatile cast in rcu_dereference() prevents the
+ compiler from deducing the resulting pointer value. Please see
+ the section entitled "EXAMPLE WHERE THE COMPILER KNOWS TOO MUCH"
+ for an example where the compiler can in fact deduce the exact
+ value of the pointer, and thus cause misordering.
+
+o Do not use single-element RCU-protected arrays. The compiler
+ is within its right to assume that the value of an index into
+ such an array must necessarily evaluate to zero. The compiler
+ could then substitute the constant zero for the computation, so
+ that the array index no longer depended on the value returned
+ by rcu_dereference(). If the array index no longer depends
+ on rcu_dereference(), then both the compiler and the CPU
+ are within their rights to order the array access before the
+ rcu_dereference(), which can cause the array access to return
+ garbage.
+
+o Avoid cancellation when using the "+" and "-" infix arithmetic
+ operators. For example, for a given variable "x", avoid
+ "(x-x)". There are similar arithmetic pitfalls from other
+ arithmetic operatiors, such as "(x*0)", "(x/(x+1))" or "(x%1)".
+ The compiler is within its rights to substitute zero for all of
+ these expressions, so that subsequent accesses no longer depend
+ on the rcu_dereference(), again possibly resulting in bugs due
+ to misordering.
+
+ Of course, if "p" is a pointer from rcu_dereference(), and "a"
+ and "b" are integers that happen to be equal, the expression
+ "p+a-b" is safe because its value still necessarily depends on
+ the rcu_dereference(), thus maintaining proper ordering.
+
+o Avoid all-zero operands to the bitwise "&" operator, and
+ similarly avoid all-ones operands to the bitwise "|" operator.
+ If the compiler is able to deduce the value of such operands,
+ it is within its rights to substitute the corresponding constant
+ for the bitwise operation. Once again, this causes subsequent
+ accesses to no longer depend on the rcu_dereference(), causing
+ bugs due to misordering.
+
+ Please note that single-bit operands to bitwise "&" can also
+ be dangerous. At this point, the compiler knows that the
+ resulting value can only take on one of two possible values.
+ Therefore, a very small amount of additional information will
+ allow the compiler to deduce the exact value, which again can
+ result in misordering.
+
+o If you are using RCU to protect JITed functions, so that the
+ "()" function-invocation operator is applied to a value obtained
+ (directly or indirectly) from rcu_dereference(), you may need to
+ interact directly with the hardware to flush instruction caches.
+ This issue arises on some systems when a newly JITed function is
+ using the same memory that was used by an earlier JITed function.
+
+o Do not use the results from the boolean "&&" and "||" when
+ dereferencing. For example, the following (rather improbable)
+ code is buggy:
+
+ int a[2];
+ int index;
+ int force_zero_index = 1;
+
+ ...
+
+ r1 = rcu_dereference(i1)
+ r2 = a[r1 && force_zero_index]; /* BUGGY!!! */
+
+ The reason this is buggy is that "&&" and "||" are often compiled
+ using branches. While weak-memory machines such as ARM or PowerPC
+ do order stores after such branches, they can speculate loads,
+ which can result in misordering bugs.
+
+o Do not use the results from relational operators ("==", "!=",
+ ">", ">=", "<", or "<=") when dereferencing. For example,
+ the following (quite strange) code is buggy:
+
+ int a[2];
+ int index;
+ int flip_index = 0;
+
+ ...
+
+ r1 = rcu_dereference(i1)
+ r2 = a[r1 != flip_index]; /* BUGGY!!! */
+
+ As before, the reason this is buggy is that relational operators
+ are often compiled using branches. And as before, although
+ weak-memory machines such as ARM or PowerPC do order stores
+ after such branches, but can speculate loads, which can again
+ result in misordering bugs.
+
+o Be very careful about comparing pointers obtained from
+ rcu_dereference() against non-NULL values. As Linus Torvalds
+ explained, if the two pointers are equal, the compiler could
+ substitute the pointer you are comparing against for the pointer
+ obtained from rcu_dereference(). For example:
+
+ p = rcu_dereference(gp);
+ if (p == &default_struct)
+ do_default(p->a);
+
+ Because the compiler now knows that the value of "p" is exactly
+ the address of the variable "default_struct", it is free to
+ transform this code into the following:
+
+ p = rcu_dereference(gp);
+ if (p == &default_struct)
+ do_default(default_struct.a);
+
+ On ARM and Power hardware, the load from "default_struct.a"
+ can now be speculated, such that it might happen before the
+ rcu_dereference(). This could result in bugs due to misordering.
+
+ However, comparisons are OK in the following cases:
+
+ o The comparison was against the NULL pointer. If the
+ compiler knows that the pointer is NULL, you had better
+ not be dereferencing it anyway. If the comparison is
+ non-equal, the compiler is none the wiser. Therefore,
+ it is safe to compare pointers from rcu_dereference()
+ against NULL pointers.
+
+ o The pointer is never dereferenced after being compared.
+ Since there are no subsequent dereferences, the compiler
+ cannot use anything it learned from the comparison
+ to reorder the non-existent subsequent dereferences.
+ This sort of comparison occurs frequently when scanning
+ RCU-protected circular linked lists.
+
+ o The comparison is against a pointer pointer that
+ references memory that was initialized "a long time ago."
+ The reason this is safe is that even if misordering
+ occurs, the misordering will not affect the accesses
+ that follow the comparison. So exactly how long ago is
+ "a long time ago"? Here are some possibilities:
+
+ o Compile time.
+
+ o Boot time.
+
+ o Module-init time for module code.
+
+ o Prior to kthread creation for kthread code.
+
+ o During some prior acquisition of the lock that
+ we now hold.
+
+ o Before mod_timer() time for a timer handler.
+
+ There are many other possibilities involving the Linux
+ kernel's wide array of primitives that cause code to
+ be invoked at a later time.
+
+ o The pointer being compared against also came from
+ rcu_dereference(). In this case, both pointers depend
+ on one rcu_dereference() or another, so you get proper
+ ordering either way.
+
+ That said, this situation can make certain RCU usage
+ bugs more likely to happen. Which can be a good thing,
+ at least if they happen during testing. An example
+ of such an RCU usage bug is shown in the section titled
+ "EXAMPLE OF AMPLIFIED RCU-USAGE BUG".
+
+ o All of the accesses following the comparison are stores,
+ so that a control dependency preserves the needed ordering.
+ That said, it is easy to get control dependencies wrong.
+ Please see the "CONTROL DEPENDENCIES" section of
+ Documentation/memory-barriers.txt for more details.
+
+ o The pointers compared not-equal -and- the compiler does
+ not have enough information to deduce the value of the
+ pointer. Note that the volatile cast in rcu_dereference()
+ will normally prevent the compiler from knowing too much.
+
+o Disable any value-speculation optimizations that your compiler
+ might provide, especially if you are making use of feedback-based
+ optimizations that take data collected from prior runs. Such
+ value-speculation optimizations reorder operations by design.
+
+ There is one exception to this rule: Value-speculation
+ optimizations that leverage the branch-prediction hardware are
+ safe on strongly ordered systems (such as x86), but not on weakly
+ ordered systems (such as ARM or Power). Choose your compiler
+ command-line options wisely!
+
+
+EXAMPLE OF AMPLIFIED RCU-USAGE BUG
+
+Because updaters can run concurrently with RCU readers, RCU readers can
+see stale and/or inconsistent values. If RCU readers need fresh or
+consistent values, which they sometimes do, they need to take proper
+precautions. To see this, consider the following code fragment:
+
+ struct foo {
+ int a;
+ int b;
+ int c;
+ };
+ struct foo *gp1;
+ struct foo *gp2;
+
+ void updater(void)
+ {
+ struct foo *p;
+
+ p = kmalloc(...);
+ if (p == NULL)
+ deal_with_it();
+ p->a = 42; /* Each field in its own cache line. */
+ p->b = 43;
+ p->c = 44;
+ rcu_assign_pointer(gp1, p);
+ p->b = 143;
+ p->c = 144;
+ rcu_assign_pointer(gp2, p);
+ }
+
+ void reader(void)
+ {
+ struct foo *p;
+ struct foo *q;
+ int r1, r2;
+
+ p = rcu_dereference(gp2);
+ r1 = p->b; /* Guaranteed to get 143. */
+ q = rcu_dereference(gp1);
+ if (p == q) {
+ /* The compiler decides that q->c is same as p->c. */
+ r2 = p->c; /* Could get 44 on weakly order system. */
+ }
+ }
+
+You might be surprised that the outcome (r1 == 143 && r2 == 44) is possible,
+but you should not be. After all, the updater might have been invoked
+a second time between the time reader() loaded into "r1" and the time
+that it loaded into "r2". The fact that this same result can occur due
+to some reordering from the compiler and CPUs is beside the point.
+
+But suppose that the reader needs a consistent view?
+
+Then one approach is to use locking, for example, as follows:
+
+ struct foo {
+ int a;
+ int b;
+ int c;
+ spinlock_t lock;
+ };
+ struct foo *gp1;
+ struct foo *gp2;
+
+ void updater(void)
+ {
+ struct foo *p;
+
+ p = kmalloc(...);
+ if (p == NULL)
+ deal_with_it();
+ spin_lock(&p->lock);
+ p->a = 42; /* Each field in its own cache line. */
+ p->b = 43;
+ p->c = 44;
+ spin_unlock(&p->lock);
+ rcu_assign_pointer(gp1, p);
+ spin_lock(&p->lock);
+ p->b = 143;
+ p->c = 144;
+ spin_unlock(&p->lock);
+ rcu_assign_pointer(gp2, p);
+ }
+
+ void reader(void)
+ {
+ struct foo *p;
+ struct foo *q;
+ int r1, r2;
+
+ p = rcu_dereference(gp2);
+ spin_lock(&p->lock);
+ r1 = p->b; /* Guaranteed to get 143. */
+ q = rcu_dereference(gp1);
+ if (p == q) {
+ /* The compiler decides that q->c is same as p->c. */
+ r2 = p->c; /* Could get 44 on weakly order system. */
+ }
+ spin_unlock(&p->lock);
+ }
+
+As always, use the right tool for the job!
+
+
+EXAMPLE WHERE THE COMPILER KNOWS TOO MUCH
+
+If a pointer obtained from rcu_dereference() compares not-equal to some
+other pointer, the compiler normally has no clue what the value of the
+first pointer might be. This lack of knowledge prevents the compiler
+from carrying out optimizations that otherwise might destroy the ordering
+guarantees that RCU depends on. And the volatile cast in rcu_dereference()
+should prevent the compiler from guessing the value.
+
+But without rcu_dereference(), the compiler knows more than you might
+expect. Consider the following code fragment:
+
+ struct foo {
+ int a;
+ int b;
+ };
+ static struct foo variable1;
+ static struct foo variable2;
+ static struct foo *gp = &variable1;
+
+ void updater(void)
+ {
+ initialize_foo(&variable2);
+ rcu_assign_pointer(gp, &variable2);
+ /*
+ * The above is the only store to gp in this translation unit,
+ * and the address of gp is not exported in any way.
+ */
+ }
+
+ int reader(void)
+ {
+ struct foo *p;
+
+ p = gp;
+ barrier();
+ if (p == &variable1)
+ return p->a; /* Must be variable1.a. */
+ else
+ return p->b; /* Must be variable2.b. */
+ }
+
+Because the compiler can see all stores to "gp", it knows that the only
+possible values of "gp" are "variable1" on the one hand and "variable2"
+on the other. The comparison in reader() therefore tells the compiler
+the exact value of "p" even in the not-equals case. This allows the
+compiler to make the return values independent of the load from "gp",
+in turn destroying the ordering between this load and the loads of the
+return values. This can result in "p->b" returning pre-initialization
+garbage values.
+
+In short, rcu_dereference() is -not- optional when you are going to
+dereference the resulting pointer.
--
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