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Date:	Fri, 21 Mar 2014 14:35:25 +0100
From:	Oliver Neukum <>
Subject: Re: Bug 71331 - mlock yields processor to lower priority process

On Fri, 2014-03-21 at 12:18 +0000, wrote:
> >How is that different from any other time a task has to yield the CPU
> >for a bit?  While your high priority task is blocked for whatever
> >reason, a lower priority task gets to use the CPU.
> As the submitter of the bug, let me give you my perspective.  SCHED_FIFO means run my task until it blocks or a higher priority task pre-empts it.  Period.
> mlock() doesn't block.  check the man page.

It guarantees that all pages be in RAM. That means it has to read them
in if they aren't. How could it do that without blocking?


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