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Message-ID: <CAKfTPtCVyLRG-fSge1shdw5aSDB3y=_qzU1DOVgCx0VBnn6mnA@mail.gmail.com>
Date: Wed, 4 Jun 2014 13:07:29 +0200
From: Vincent Guittot <vincent.guittot@...aro.org>
To: Morten Rasmussen <morten.rasmussen@....com>
Cc: Peter Zijlstra <peterz@...radead.org>,
"mingo@...nel.org" <mingo@...nel.org>,
"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
"linux@....linux.org.uk" <linux@....linux.org.uk>,
"linux-arm-kernel@...ts.infradead.org"
<linux-arm-kernel@...ts.infradead.org>,
"preeti@...ux.vnet.ibm.com" <preeti@...ux.vnet.ibm.com>,
"efault@....de" <efault@....de>,
"nicolas.pitre@...aro.org" <nicolas.pitre@...aro.org>,
"linaro-kernel@...ts.linaro.org" <linaro-kernel@...ts.linaro.org>,
"daniel.lezcano@...aro.org" <daniel.lezcano@...aro.org>
Subject: Re: [PATCH v2 08/11] sched: get CPU's activity statistic
On 4 June 2014 12:36, Morten Rasmussen <morten.rasmussen@....com> wrote:
> On Wed, Jun 04, 2014 at 11:17:24AM +0100, Peter Zijlstra wrote:
>> On Wed, Jun 04, 2014 at 11:32:10AM +0200, Vincent Guittot wrote:
>> > On 4 June 2014 10:08, Peter Zijlstra <peterz@...radead.org> wrote:
>> > > On Wed, Jun 04, 2014 at 09:47:26AM +0200, Vincent Guittot wrote:
>> > >> On 3 June 2014 17:50, Peter Zijlstra <peterz@...radead.org> wrote:
>> > >> > On Wed, May 28, 2014 at 04:47:03PM +0100, Morten Rasmussen wrote:
>> > >> >> Since we may do periodic load-balance every 10 ms or so, we will perform
>> > >> >> a number of load-balances where runnable_avg_sum will mostly be
>> > >> >> reflecting the state of the world before a change (new task queued or
>> > >> >> moved a task to a different cpu). If you had have two tasks continuously
>> > >> >> on one cpu and your other cpu is idle, and you move one of the tasks to
>> > >> >> the other cpu, runnable_avg_sum will remain unchanged, 47742, on the
>> > >> >> first cpu while it starts from 0 on the other one. 10 ms later it will
>> > >> >> have increased a bit, 32 ms later it will be 47742/2, and 345 ms later
>> > >> >> it reaches 47742. In the mean time the cpu doesn't appear fully utilized
>> > >> >> and we might decide to put more tasks on it because we don't know if
>> > >> >> runnable_avg_sum represents a partially utilized cpu (for example a 50%
>> > >> >> task) or if it will continue to rise and eventually get to 47742.
>> > >> >
>> > >> > Ah, no, since we track per task, and update the per-cpu ones when we
>> > >> > migrate tasks, the per-cpu values should be instantly updated.
>> > >> >
>> > >> > If we were to increase per task storage, we might as well also track
>> > >> > running_avg not only runnable_avg.
>> > >>
>> > >> I agree that the removed running_avg should give more useful
>> > >> information about the the load of a CPU.
>> > >>
>> > >> The main issue with running_avg is that it's disturbed by other tasks
>> > >> (as point out previously). As a typical example, if we have 2 tasks
>> > >> with a load of 25% on 1 CPU, the unweighted runnable_load_avg will be
>> > >> in the range of [100% - 50%] depending of the parallelism of the
>> > >> runtime of the tasks whereas the reality is 50% and the use of
>> > >> running_avg will return this value
>> > >
>> > > I'm not sure I see how 100% is possible, but yes I agree that runnable
>> > > can indeed be inflated due to this queueing effect.
>>
>> Let me explain the 75%, take any one of the above scenarios. Lets call
>> the two tasks A and B, and let for a moment assume A always wins and
>> runs first, and then B.
>>
>> So A will be runnable for 25%, B otoh will be runnable the entire time A
>> is actually running plus its own running time, giving 50%. Together that
>> makes 75%.
>>
>> If you release the assumption that A runs first, but instead assume they
>> equally win the first execution, you get them averaging at 37.5% each,
>> which combined will still give 75%.
>
> But that is assuming that the first task gets to run to completion of it
> busy period. If it uses up its sched_slice and we switch to the other
> tasks, they both get to wait.
>
> For example, if the sched_slice is 5 ms and the busy period is 10 ms,
> the execution pattern would be: A, B, A, B, idle, ... In that case A is
> runnable for 15 ms and B is for 20 ms. Assuming that the overall period
> is 40 ms, the A runnable is 37.5% and B is 50%.
The exact value for your scheduling example above is:
A runnable will be 47% and B runnable will be 60% (unless i make a
mistake in my computation)
and CPU runnable will be 60% too
Vincent
>
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