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Message-ID: <1402461178.24669.40.camel@localhost>
Date: Wed, 11 Jun 2014 14:32:58 +1000
From: wmealing <wmealing@...il.com>
To: linux-kernel@...r.kernel.org
Cc: wmealing@...hat.com
Subject: Counting currently open file descriptors per process.
Gday,
I'm seeking some guidance on how to best (or if) to implement a feature.
Please CC me on any reply, I am not subscribed to this list.
The feature is, "an application would like to know how many files another
process has open".
>From user space, the cheapest way would be to use the call
syscall(SYS_getdents ...) in the proc/pid/fd directory.
Alternatively from kernel space one could achieve a similar behavior by
iterating through the tasks fdtable, as i have attempted to here:
https://gist.github.com/wmealing/c0836bc6a38f8f90aa0d
Colleagues of mine have pointed out that this may have performance
impacts for tools that frequently parse /proc/pid/status.
I have compiled a kernel with the above patch and here are the performance stats.
System settings
# sysctl -w fs.file-max=5000000
fs.file-max = 5000000
Increase this sessions limits.
# ulimit -n 1000000
test.py had 500002 files open each time.
Here are some of the performance benchmarks on an idle
system:
# time cat /proc/`pidof python test.py`/status |grep FD
FDSize: 524288
FDCount: 500002
real 0m0.008s
user 0m0.002s
sys 0m0.004s
# time ./test-getdents /proc/`pidof python test.py`/fd &> /dev/null
real 0m0.631s
user 0m0.001s
sys 0m0.485s
or this time with readdir(3)
# time ./test-opendir /proc/`pidof python test.py`/fd &> /dev/null
real 0m0.129s
user 0m0.001s
sys 0m0.007s
(which oddly seems faster?)
My benchmark values above are not meant for micro-benchmarking
but rather as a scale to know how far behind the code is.
Is the current method of getting a live fd count acceptable, if
not how should it be done ?
Thanks for your time.
Wade Mealing.
[1] https://github.com/wmealing/live-fd-count/
git repo with code used in the above.
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