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Message-ID: <CAJhHMCDaMH0b0Np8vNf=RBH8i76AUK78qf213aWfHY-F4j3OOw@mail.gmail.com>
Date: Thu, 28 Aug 2014 17:45:10 -0400
From: Pranith Kumar <bobby.prani@...il.com>
To: Paul McKenney <paulmck@...ux.vnet.ibm.com>
Cc: Randy Dunlap <rdunlap@...radead.org>,
"open list:DOCUMENTATION" <linux-doc@...r.kernel.org>,
LKML <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH] doc: memory-barriers.txt: Correct example for reorderings
On Thu, Aug 28, 2014 at 5:39 PM, Paul E. McKenney
<paulmck@...ux.vnet.ibm.com> wrote:
> On Thu, Aug 28, 2014 at 05:15:50PM -0400, Pranith Kumar wrote:
>> On Thu, Aug 28, 2014 at 5:00 PM, Paul E. McKenney
>> <paulmck@...ux.vnet.ibm.com> wrote:
>> >
>> > I am really confused by the ordering of the new lines, as I would have
>> > expected the "x"s to be replaced with "y"s and vice versa. But the
>> > ordering of the various combinations does not matter, and each line
>> > looks OK.
>>
>> Since x = A was replaced by x = B and y = B was replaced by y = A, I
>> just converted all x = load A to x = load B. Similarly for y. I think
>> we can do either this or as you suggested replacing x's with y's.
>
> Fair enough. The other thing that confused me was the "STORE B=4,"
> showing up early in your replacement.
>
So I converted
STORE A=3, x=LOAD A->3
to
STORE B=4, x=LOAD B->4
since the later load into x wanted an updated value of B and not the
default. That is the reason you see STORE B = 4 in place of STORE A =
3
--
Pranith
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