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Message-ID: <CAJhHMCC98dPnx=ng3zp5ZZmzOZkdPXaA1bmcQJuhQj9wb7CRhw@mail.gmail.com>
Date:	Fri, 27 Feb 2015 13:25:25 -0500
From:	Pranith Kumar <bobby.prani@...il.com>
To:	Will Deacon <will.deacon@....com>
Cc:	Catalin Marinas <Catalin.Marinas@....com>,
	Steve Capper <steve.capper@...aro.org>,
	"linux-arm-kernel@...ts.infradead.org" 
	<linux-arm-kernel@...ts.infradead.org>,
	open list <linux-kernel@...r.kernel.org>
Subject: Re: [RFC PATCH] ARM64: cmpxchg.h: Clear the exclusive access bit on fail

On Fri, Feb 27, 2015 at 5:06 AM, Will Deacon <will.deacon@....com> wrote:
> On Fri, Feb 27, 2015 at 05:46:55AM +0000, Pranith Kumar wrote:
>> In cmpxchg(), we do a load exclusive on an address and upon a comparison fail,
>> we skip the store exclusive instruction. This can result in the exclusive bit
>> still set. If there was a store exclusive after this to the same address, that
>> will see the exclusive bit set. This should not happen.
>
> ... and the problem with that is?

Consider the following scenario:

            P0                    P1
            ---------------------------------
            ldxr x7, [B]                         // exclusive bit set
            add  x7, x7, #1
                                str ..., [B]     // exclusive bit cleared
cmpxchg:
            ldxr x0, [B]                         // exclusive bit set
            cmp  x0, #0                        // cmp fails
            b.ne 1f                               // branch taken
            stxr x1, [B]                         // end of cmpxchg
1:
            stxr x7, [B]                        // succeeds?


    The last store exclusive succeeds since the exclusive bit is set which
should not happen. Clearing the exclusive bit before returning from cmpxchg
prevents this happening.

Now I am not sure how likely this will happen. One can argue that a cmpxchg()
will not happen between an external ldxr/stxr. But isn't clearing the exclusive
bit better?

-- 
Pranith
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