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Message-ID: <alpine.LSU.2.20.1505061255360.8975@nerf40.vanv.qr>
Date:	Wed, 6 May 2015 12:57:08 +0200 (CEST)
From:	Jan Engelhardt <jengelh@...i.de>
To:	"long.wanglong" <long.wanglong@...wei.com>
cc:	torvalds@...ux-foundation.org, jay.foad@...il.com,
	cwhuang@...roid-x86.org, akpm@...ux-foundation.org,
	kirill.shutemov@...ux.intel.com, riel@...hat.com,
	sasha.levin@...cle.com, Michal Hocko <mhocko@...e.cz>,
	dave@...olabs.net, koct9i@...il.com, luto@...capital.net,
	pfeiner@...gle.com, dh.herrmann@...il.com, vishnu.ps@...sung.com,
	linux-mm@...ck.org,
	"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
	Wang Kai <morgan.wang@...wei.com>,
	peifeiyue <peifeiyue@...wei.com>, linux-arch@...r.kernel.org
Subject: Re: [RFC] kernel random segmentation fault?


On Wednesday 2015-05-06 05:46, long.wanglong wrote:
>
>int main(int argc, char** argv)
>{
>    rlim.rlim_cur=20 MB;
>    rlim.rlim_max=20 MB;
>    ret = setrlimit(RLIMIT_AS, &rlim);
>    [...]
>    char tmp[20 MB];
>    for (i = 0; i < 20 MB; i++)
>        tmp[i]=1;

if tmp already takes 20 MB, where will the remainder of the program find
space if you only allow for 20 MB? This is bound to fail under normal
considerations.
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