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Date: Tue, 7 Jul 2015 14:10:56 +0200
From: Fredrik Markström <fredrik.markstrom@...il.com>
To: Peter Zijlstra <peterz@...radead.org>
Cc: Frederic Weisbecker <fweisbec@...il.com>, mingo@...hat.com,
linux-kernel@...r.kernel.org, Rik van Riel <riel@...hat.com>,
Jason Low <jason.low2@...com>
Subject: Re: [PATCH 1/1] cputime: Make the reported utime+stime correspond to
the actual runtime.
Just to let you know, I've tested your last patch and it solves all my
original problems (which is should since the code is functionally
equivalent).
/Fredrik
On Tue, Jul 7, 2015 at 10:09 AM, Peter Zijlstra <peterz@...radead.org> wrote:
> On Tue, Jul 07, 2015 at 09:59:54AM +0200, Peter Zijlstra wrote:
>> > > + /*
>> > > + * Make sure stime doesn't go backwards; this preserves monotonicity
>> > > + * for utime because rtime is monotonic.
>> > > + *
>> > > + * utime_i+1 = rtime_i+1 - stime_i
>> > > + * = rtime_i+1 - (rtime_i - stime_i)
>> > > + * = (rtime_i+1 - rtime_i) + stime_i
>> > > + * >= stime_i
>> > > + */
>
> Argh, just noticed I messed that up, it should read:
>
> + /*
> + * Make sure stime doesn't go backwards; this preserves monotonicity
> + * for utime because rtime is monotonic.
> + *
> + * utime_i+1 = rtime_i+1 - stime_i
> + * = rtime_i+1 - (rtime_i - utime_i)
> + * = (rtime_i+1 - rtime_i) + utime_i
> + * >= utime_i
> + */
>
> I got some [us] confusion. Typing is hard.
>
> So we compute: utime = rtime - stime, which we'll denote as:
>
> utime_i+1 = rtime_i+1 - stime_i
>
> since: stime_i + utime_i = rtime_i, we can write: stime_i = rtime_i -
> utime_i and substitute in the above:
>
> = rtime_i+1 - (rtime_i - utime_i)
>
> Rearrange terms:
>
> = (rtime_i+1 - rtime_i) + utime_i
>
> And since we have: rtime_i+1 >= rtime_i, which we can write like:
> rtime_i+1 - rtime_i >= 0, substitution gives:
>
> >= utime_i
>
> And we've proven that the new utime must be equal or greater than the
> previous utime, because rtime is monotonic.
--
/Fredrik
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