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Message-ID: <alpine.DEB.2.11.1509080959460.15006@nanos>
Date: Tue, 8 Sep 2015 10:09:28 +0200 (CEST)
From: Thomas Gleixner <tglx@...utronix.de>
To: Ingo Molnar <mingo@...nel.org>
cc: Steven Rostedt <rostedt@...dmis.org>, linux-kernel@...r.kernel.org,
linux-rt-users <linux-rt-users@...r.kernel.org>,
Carsten Emde <C.Emde@...dl.org>,
Sebastian Andrzej Siewior <bigeasy@...utronix.de>,
John Kacur <jkacur@...hat.com>,
Paul Gortmaker <paul.gortmaker@...driver.com>,
Peter Zijlstra <peterz@...radead.org>,
Clark Williams <clark.williams@...il.com>,
Arnaldo Carvalho de Melo <acme@...hat.com>
Subject: Re: [RFC][PATCH RT 0/3] RT: Fix trylock deadlock without msleep()
hack
On Tue, 8 Sep 2015, Ingo Molnar wrote:
>
> * Thomas Gleixner <tglx@...utronix.de> wrote:
>
> > 3) sched_yield() makes me shudder
> >
> > CPU0 CPU1
> >
> > taskA
> > lock(x->lock)
> >
> > preemption
> > taskC
> > taskB
> > lock(y->lock);
> > x = y->x;
> > if (!try_lock(x->lock)) {
> > unlock(y->lock);
> > boost(taskA);
> > sched_yield(); <- returns immediately
>
> So I'm still struggling with properly parsing the usecase.
>
> If y->x might become invalid the moment we drop y->lock, what makes
> the 'taskA' use (after we've dropped y->lock) safe? Shouldn't we at
> least also have a task_get(taskA)/task_put(taskA) reference count,
> to make sure the boosted task stays around?
Stevens trylock_and_boost() function makes sure that taskA cannot go
away while doing the boosting. It's a bug in my pseudo code, but that
does not make the issue above going away.
> And if we are into getting reference counts, why not solve it at a
> higher level and get a reference count to 'x' to make sure it's safe
> to use? Then we could do:
>
> lock(y->lock);
> retry:
> x = y->x;
> if (!trylock(x->lock)) {
> get_ref(x->count)
> unlock(y->lock);
> lock(x->lock);
> lock(y->lock);
> put_ref(x->count);
> if (y->x != x) { /* Retry if 'x' got dropped meanwhile */
> unlock(x->lock);
> goto retry;
> }
> }
>
> Or so.
In the case of dcache::dentry_kill() we probably do not have to take
refcounts and it might be actually counterproductive to do so. y->x,
i.e. dentry->parent, cannot vanish under us, if I understand the life
time rules correctly.
Aside of that, yes, I was thinking about a similar scheme for
that. I need some more time to grok all the rules there :)
Thanks,
tglx
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