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Message-ID: <20151008125800.GC14829@krava.landal.opennet>
Date: Thu, 8 Oct 2015 14:58:00 +0200
From: Jiri Olsa <jolsa@...hat.com>
To: Namhyung Kim <namhyung@...nel.org>
Cc: Arnaldo Carvalho de Melo <acme@...nel.org>,
Ingo Molnar <mingo@...nel.org>,
Peter Zijlstra <a.p.zijlstra@...llo.nl>,
LKML <linux-kernel@...r.kernel.org>,
Frederic Weisbecker <fweisbec@...il.com>,
Stephane Eranian <eranian@...gle.com>,
David Ahern <dsahern@...il.com>,
Andi Kleen <andi@...stfloor.org>
Subject: Re: [RFC/PATCH 17/38] perf tools: Maintain map groups list in a
leader thread
On Fri, Oct 02, 2015 at 02:18:58PM +0900, Namhyung Kim wrote:
SNIP
> int __thread__set_comm(struct thread *thread, const char *str, u64 timestamp,
> bool exec)
> {
> @@ -182,6 +257,40 @@ int __thread__set_comm(struct thread *thread, const char *str, u64 timestamp,
> unwind__flush_access(thread);
> }
>
> + if (exec) {
> + struct machine *machine;
> +
> + BUG_ON(thread->mg == NULL || thread->mg->machine == NULL);
> +
> + machine = thread->mg->machine;
> +
> + if (thread->tid != thread->pid_) {
> + struct map_groups *old = thread->mg;
> + struct thread *leader;
> +
> + leader = machine__findnew_thread(machine, thread->pid_,
> + thread->pid_);
> +
> + /* now it'll be a new leader */
> + thread->pid_ = thread->tid;
> +
> + thread->mg = map_groups__new(old->machine);
> + if (thread->mg == NULL)
> + return -ENOMEM;
> +
> + /* save current mg in the new leader */
> + thread__clone_map_groups(thread, leader);
> +
> + /* current mg of leader thread needs one more refcnt */
> + map_groups__get(thread->mg);
> +
> + thread__set_map_groups(thread, thread->mg, old->timestamp);
> + }
> +
> + /* create a new mg for newly executed binary */
> + thread__set_map_groups(thread, map_groups__new(machine), timestamp);
should this ^^^^ be in the else case of above condition?
also thread__fork calls thread__clone_map_groups once again,
I have some difficulty to sort this out ATM.. is that correct?
some comment on how we treat map groups in general (for fork/clone/exit)
would be awesome ;-)
thanks,
jirka
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