commit d7e35dfa2531b53618b9e6edcd8752ce988ac555 Author: Sasha Levin Date: Thu Dec 3 22:04:01 2015 -0500 bitops.h: correctly handle rol32 with 0 byte shift ROL on a 32 bit integer with a shift of 32 or more is undefined and the result is arch-dependent. Avoid this by handling the trivial case of roling by 0 correctly. The trivial solution of checking if shift is 0 breaks gcc's detection of this code as a ROL instruction, which is unacceptable. This bug was reported and fixed in GCC (https://gcc.gnu.org/bugzilla/show_bug.cgi?id=57157): The standard rotate idiom, (x << n) | (x >> (32 - n)) is recognized by gcc (for concreteness, I discuss only the case that x is an uint32_t here). However, this is portable C only for n in the range 0 < n < 32. For n == 0, we get x >> 32 which gives undefined behaviour according to the C standard (6.5.7, Bitwise shift operators). To portably support n == 0, one has to write the rotate as something like (x << n) | (x >> ((-n) & 31)) And this is apparently not recognized by gcc. Note that this is broken on older GCCs and will result in slower ROL. Acked-by: Linus Torvalds Signed-off-by: Sasha Levin Signed-off-by: Linus Torvalds diff --git a/include/linux/bitops.h b/include/linux/bitops.h index 2b8ed12..defeaac 100644 --- a/include/linux/bitops.h +++ b/include/linux/bitops.h @@ -107,7 +107,7 @@ static inline __u64 ror64(__u64 word, unsigned int shift) */ static inline __u32 rol32(__u32 word, unsigned int shift) { - return (word << shift) | (word >> (32 - shift)); + return (word << shift) | (word >> ((-shift) & 31)); } /**