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Message-ID: <alpine.DEB.2.11.1606101716530.5839@nanos>
Date: Fri, 10 Jun 2016 17:20:43 +0200 (CEST)
From: Thomas Gleixner <tglx@...utronix.de>
To: Nicolas Pitre <nicolas.pitre@...aro.org>
cc: Daniel Lezcano <daniel.lezcano@...aro.org>,
shreyas@...ux.vnet.ibm.com, linux-kernel@...r.kernel.org,
peterz@...radead.org, rafael@...nel.org, vincent.guittot@...aro.org
Subject: Re: [PATCH V4] irq: Track the interrupt timings
On Fri, 10 Jun 2016, Nicolas Pitre wrote:
> On Fri, 10 Jun 2016, Thomas Gleixner wrote:
> > > + diff = now - prev;
> > > +
> > > + /*
> > > + * microsec (actually 1024th of a milisec) precision is good
> > > + * enough for our purpose.
> > > + */
> > > + diff >>= 10;
> >
> > And that shift instruction is required because of the following?
> >
> > > * Otherwise we know the magnitude of diff is
> > > + * well within 32 bits.
> >
> > AFAICT that's pointless. You are not saving anything because NSEC_PER_SEC is
> > smaller than 2^32 and your 8 values are not going to overflow 64 bit in the
> > sum.
>
> Those values are squared later, so we really want 32 bits here.
Well, you can do sum >> 10 exaclty once when you calculate stuff.
> > > + */
> > > + if (unlikely(diff > USEC_PER_SEC)) {
> > > + memset(timings, 0, sizeof(*timings));
> > > + timings->timestamp = now;
> >
> > Redundant store.
>
> We just trashed all our data with the memset so the current timestamp
> needs to be restored.
So why doing a full memset and not only on the array ?
> > Now the real question is whether you really need all that math, checks and
> > memsets in the irq hotpath. If you make the storage slightly larger then you
> > can just store the values unconditionally in the circular buffer and do all
> > the computational stuff when you really it.
>
> Well... given that you need an IRQ everytime you come out of idle that
> means there will always be more IRQs than entries into idle, so you're
> probably right.
Glad you agree.
Thanks,
tglx
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