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Date:	Tue, 16 Aug 2016 15:57:06 +0200
From:	Vincent Guittot <vincent.guittot@...aro.org>
To:	Morten Rasmussen <morten.rasmussen@....com>
Cc:	Peter Zijlstra <peterz@...radead.org>,
	"mingo@...hat.com" <mingo@...hat.com>,
	Dietmar Eggemann <dietmar.eggemann@....com>,
	Yuyang Du <yuyang.du@...el.com>, mgalbraith@...e.de,
	Sai Charan Gurrappadi <sgurrappadi@...dia.com>,
	Koan-Sin Tan <freedom.tan@...iatek.com>,
	小林敬太 <keita.kobayashi.ym@...esas.com>,
	linux-kernel <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH v3 11/13] sched/fair: Consider spare capacity in find_idlest_group()

On 25 July 2016 at 15:34, Morten Rasmussen <morten.rasmussen@....com> wrote:
> In low-utilization scenarios comparing relative loads in
> find_idlest_group() doesn't always lead to the most optimum choice.
> Systems with groups containing different numbers of cpus and/or cpus of
> different compute capacity are significantly better off when considering
> spare capacity rather than relative load in those scenarios.
>
> In addition to existing load based search an alternative spare capacity
> based candidate sched_group is found and selected instead if sufficient
> spare capacity exists. If not, existing behaviour is preserved.
>
> cc: Ingo Molnar <mingo@...hat.com>
> cc: Peter Zijlstra <peterz@...radead.org>
>
> Signed-off-by: Morten Rasmussen <morten.rasmussen@....com>
> ---
>  kernel/sched/fair.c | 46 +++++++++++++++++++++++++++++++++++++++++-----
>  1 file changed, 41 insertions(+), 5 deletions(-)
>
> diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c
> index 9c6ec3bf75ce..e3654409d099 100644
> --- a/kernel/sched/fair.c
> +++ b/kernel/sched/fair.c
> @@ -5164,6 +5164,14 @@ static int wake_affine(struct sched_domain *sd, struct task_struct *p,
>         return 1;
>  }
>
> +static inline int task_util(struct task_struct *p);
> +static int cpu_util_wake(int cpu, struct task_struct *p);
> +
> +static unsigned long capacity_spare_wake(int cpu, struct task_struct *p)
> +{
> +       return capacity_orig_of(cpu) - cpu_util_wake(cpu, p);
> +}
> +
>  /*
>   * find_idlest_group finds and returns the least busy CPU group within the
>   * domain.
> @@ -5173,7 +5181,9 @@ find_idlest_group(struct sched_domain *sd, struct task_struct *p,
>                   int this_cpu, int sd_flag)
>  {
>         struct sched_group *idlest = NULL, *group = sd->groups;
> +       struct sched_group *most_spare_sg = NULL;
>         unsigned long min_load = ULONG_MAX, this_load = 0;
> +       unsigned long most_spare = 0, this_spare = 0;
>         int load_idx = sd->forkexec_idx;
>         int imbalance = 100 + (sd->imbalance_pct-100)/2;
>
> @@ -5181,7 +5191,7 @@ find_idlest_group(struct sched_domain *sd, struct task_struct *p,
>                 load_idx = sd->wake_idx;
>
>         do {
> -               unsigned long load, avg_load;
> +               unsigned long load, avg_load, spare_cap, max_spare_cap;
>                 int local_group;
>                 int i;
>
> @@ -5193,8 +5203,12 @@ find_idlest_group(struct sched_domain *sd, struct task_struct *p,
>                 local_group = cpumask_test_cpu(this_cpu,
>                                                sched_group_cpus(group));
>
> -               /* Tally up the load of all CPUs in the group */
> +               /*
> +                * Tally up the load of all CPUs in the group and find
> +                * the group containing the cpu with most spare capacity.
> +                */
>                 avg_load = 0;
> +               max_spare_cap = 0;
>
>                 for_each_cpu(i, sched_group_cpus(group)) {
>                         /* Bias balancing toward cpus of our domain */
> @@ -5204,6 +5218,13 @@ find_idlest_group(struct sched_domain *sd, struct task_struct *p,
>                                 load = target_load(i, load_idx);
>
>                         avg_load += load;
> +
> +                       spare_cap = capacity_spare_wake(i, p);
> +
> +                       if (spare_cap > max_spare_cap &&
> +                           spare_cap > capacity_of(i) >> 3) {

This condition probably needs some descriptions. You're not only
looking for max spare capacity but also a significant spare capacity
(more than 12.5% of cpu_capacity_orig). Can't this additional test
lead to some strange situation where a CPU with more spare capacity
will not be selected because of this 12.5% condition whereas another
with less spare capacity will be selected because its capacity_orig is
lower ?

> +                               max_spare_cap = spare_cap;
> +                       }
>                 }
>
>                 /* Adjust by relative CPU capacity of the group */
> @@ -5211,12 +5232,27 @@ find_idlest_group(struct sched_domain *sd, struct task_struct *p,
>
>                 if (local_group) {
>                         this_load = avg_load;
> -               } else if (avg_load < min_load) {
> -                       min_load = avg_load;
> -                       idlest = group;
> +                       this_spare = max_spare_cap;
> +               } else {
> +                       if (avg_load < min_load) {
> +                               min_load = avg_load;
> +                               idlest = group;
> +                       }
> +
> +                       if (most_spare < max_spare_cap) {
> +                               most_spare = max_spare_cap;
> +                               most_spare_sg = group;
> +                       }
>                 }
>         } while (group = group->next, group != sd->groups);
>
> +       /* Found a significant amount of spare capacity. */

It may worth explaining the threshold when it becomes better to choose
the most spare group instead of the least loaded group.

> +       if (this_spare > task_util(p) / 2 &&
> +           imbalance*this_spare > 100*most_spare)
> +               return NULL;
> +       else if (most_spare > task_util(p) / 2)
> +               return most_spare_sg;
> +
>         if (!idlest || 100*this_load < imbalance*min_load)
>                 return NULL;
>         return idlest;
> --
> 1.9.1
>

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