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Message-ID: <20161004151258.GD32214@dhcp22.suse.cz>
Date: Tue, 4 Oct 2016 17:12:58 +0200
From: Michal Hocko <mhocko@...nel.org>
To: Vlastimil Babka <vbabka@...e.cz>
Cc: Andrew Morton <akpm@...ux-foundation.org>,
David Rientjes <rientjes@...gle.com>,
Sellami Abdelkader <abdelkader.sellami@....com>,
linux-mm@...ck.org, LKML <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH] oom: print nodemask in the oom report
On Tue 04-10-16 17:02:42, Vlastimil Babka wrote:
> On 10/04/2016 04:16 PM, Michal Hocko wrote:
> > On Tue 04-10-16 15:24:53, Vlastimil Babka wrote:
> > > On 09/30/2016 11:41 PM, Michal Hocko wrote:
> > [...]
> > > > Fix this by always priting the nodemask. It is either mempolicy mask
> > > > (and non-null) or the one defined by the cpusets.
> > >
> > > I wonder if it's helpful to print the cpuset one when that's printed
> > > separately, and seeing both pieces of information (nodemask and cpuset)
> > > unmodified might tell us more. Is it to make it easier to deal with NULL
> > > nodemask? Or to make sure the info gets through pr_warn() and not pr_info()?
> >
> > I am not sure I understand the question. I wanted to print the nodemask
> > separatelly in the same line with all other allocation request
> > parameters like order and gfp mask because that is what the page
> > allocator got (via policy_nodemask). cpusets builds on top - aka applies
> > __cpuset_zone_allowed on top of the nodemask. So imho it makes sense to
> > look at the cpuset as an allocation domain while the mempolicy as a
> > restriction within this domain.
> >
> > Does that answer your question?
>
> Ah, I wasn't clear. What I questioned is the fallback to cpusets for NULL
> nodemask:
>
> nodemask_t *nm = (oc->nodemask) ? oc->nodemask :
> &cpuset_current_mems_allowed;
Well no nodemask means there is no mempolicy so either all nodes can be
used or they are restricted by the cpuset. cpuset_current_mems_allowed is
node_states[N_MEMORY] if there is no cpuset so I believe we are printing
the correct information. An alternative would be either not print
anything if there is no nodemask or print node_states[N_MEMORY]
regardless the cpusets. The first one is quite ugly while the later
might be confusing I guess.
--
Michal Hocko
SUSE Labs
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