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Message-ID: <20161129191612.GA31083@kroah.com>
Date: Tue, 29 Nov 2016 20:16:12 +0100
From: 'Greg Kroah-Hartman' <gregkh@...uxfoundation.org>
To: "Winkler, Tomas" <tomas.winkler@...el.com>
Cc: "Usyskin, Alexander" <alexander.usyskin@...el.com>,
"'linux-kernel@...r.kernel.org'" <linux-kernel@...r.kernel.org>
Subject: Re: [char-misc-next 4/4 V2] mei: bus: enable non-blocking RX
On Mon, Nov 28, 2016 at 11:03:20PM +0000, Winkler, Tomas wrote:
> >
> >
> > >
> > > On Sat, Nov 19, 2016 at 02:16:11PM +0200, Tomas Winkler wrote:
> > > > From: Alexander Usyskin <alexander.usyskin@...el.com>
> > > >
> > > > Enable non-blocking receive for drivers on mei bus, this allows
> > > > checking for data availability by mei client drivers. This is most
> > > > effective for fixed address clients, that lacks flow control.
> > > >
> > > > This function adds new API function mei_cldev_recv_nonblock(), it
> > > > retuns -EGAIN if function will block.
> > > >
> > > > Signed-off-by: Alexander Usyskin <alexander.usyskin@...el.com>
> > > > Signed-off-by: Tomas Winkler <tomas.winkler@...el.com>
> > > > ---
> > > > V2: use _nonblock() function suffix instead of NONBLOCK flag
> > > >
> > > > drivers/misc/mei/bus-fixup.c | 4 ++--
> > > > drivers/misc/mei/bus.c | 31 +++++++++++++++++++++++++++++--
> > > > drivers/misc/mei/mei_dev.h | 7 ++++++-
> > > > include/linux/mei_cl_bus.h | 6 ++++--
> > > > 4 files changed, 41 insertions(+), 7 deletions(-)
> > > >
> > > > diff --git a/drivers/misc/mei/bus-fixup.c
> > > > b/drivers/misc/mei/bus-fixup.c index 7f2cef9011ae..18e05ca7584f
> > > > 100644
> > > > --- a/drivers/misc/mei/bus-fixup.c
> > > > +++ b/drivers/misc/mei/bus-fixup.c
> > > > @@ -141,7 +141,7 @@ static int mei_osver(struct mei_cl_device *cldev)
> > > > if (ret < 0)
> > > > return ret;
> > > >
> > > > - ret = __mei_cl_recv(cldev->cl, buf, length);
> > > > + ret = __mei_cl_recv(cldev->cl, buf, length, 0);
> > >
> > > What is 0 here? Again, mode...
> >
> > Yes, it means no change in behavior, but this is an internal function.
So, it makes no sense, are you not going to have to read this code again
in 10 years? New developers? Make the code make sense please.
thanks,
greg k-h
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