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Message-ID: <CAFcVECJutEu2=POtAU=jX6E3-ZHsLXpOMMw+UJ0hcQgZ0n4ZVA@mail.gmail.com>
Date: Fri, 9 Dec 2016 11:07:23 +0530
From: Harini Katakam <harinikatakamlinux@...il.com>
To: Andrei Pistirica <Andrei.Pistirica@...rochip.com>
Cc: Richard Cochran <richardcochran@...il.com>, netdev@...r.kernel.org,
"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
"linux-arm-kernel@...ts.infradead.org"
<linux-arm-kernel@...ts.infradead.org>,
David Miller <davem@...emloft.net>,
Nicolas Ferre <nicolas.ferre@...el.com>,
Harini Katakam <harini.katakam@...inx.com>,
Punnaiah Choudary Kalluri <punnaia@...inx.com>,
"michals@...inx.com" <michals@...inx.com>,
Anirudha Sarangi <anirudh@...inx.com>,
Boris Brezillon <boris.brezillon@...e-electrons.com>,
alexandre.belloni@...e-electrons.com, tbultel@...elsurmer.com,
Rafal Ozieblo <rafalo@...ence.com>
Subject: Re: [RFC PATCH net-next v3 1/2] macb: Add 1588 support in Cadence GEM.
Hi,
On Thu, Dec 8, 2016 at 8:11 PM, <Andrei.Pistirica@...rochip.com> wrote:
>
>
>> -----Original Message-----
>> From: Richard Cochran [mailto:richardcochran@...il.com]
>> Sent: Wednesday, December 07, 2016 11:04 PM
>> To: Andrei Pistirica - M16132
>> Cc: netdev@...r.kernel.org; linux-kernel@...r.kernel.org; linux-arm-
>> kernel@...ts.infradead.org; davem@...emloft.net;
>> nicolas.ferre@...el.com; harinikatakamlinux@...il.com;
>> harini.katakam@...inx.com; punnaia@...inx.com; michals@...inx.com;
>> anirudh@...inx.com; boris.brezillon@...e-electrons.com;
>> alexandre.belloni@...e-electrons.com; tbultel@...elsurmer.com;
>> rafalo@...ence.com
>> Subject: Re: [RFC PATCH net-next v3 1/2] macb: Add 1588 support in
>> Cadence GEM.
>>
>> On Wed, Dec 07, 2016 at 08:39:09PM +0100, Richard Cochran wrote:
>> > > +static s32 gem_ptp_max_adj(unsigned int f_nom) {
>> > > + u64 adj;
>> > > +
>> > > + /* The 48 bits of seconds for the GEM overflows every:
>> > > + * 2^48/(365.25 * 24 * 60 *60) =~ 8 925 512 years (~= 9 mil years),
>> > > + * thus the maximum adjust frequency must not overflow CNS
>> register:
>> > > + *
>> > > + * addend = 10^9/nominal_freq
>> > > + * adj_max = +/- addend*ppb_max/10^9
>> > > + * max_ppb = (2^8-1)*nominal_freq-10^9
>> > > + */
>> > > + adj = f_nom;
>> > > + adj *= 0xffff;
>> > > + adj -= 1000000000ULL;
>> >
>> > What is this computation, and how does it relate to the comment?
>
> I considered the following simple equation: increment value at nominal frequency (which is 10^9/nominal frequency nsecs) + the maximum drift value (nsecs) <= maximum increment value at nominal frequency (which is 8bit:0xffff).
> If maximum drift is written as function of nominal frequency and maximum ppb, then the equation above yields that the maximum ppb is: (2^8 - 1) *nominal_frequency - 10^9. The equation is also simplified by the fact that the drift is written as ppm + 16bit_fractions and the increment value is written as nsec + 16bit_fractions.
>
> Rafal said that this value is hardcoded: 0x64E6, while Harini said: 250000000.
@ Andrei, I may have equated max ppb to max tsu frequency allowed on
the system and set that.
That will be wrong.
>
> I need to dig into this...
>
>>
>> I am not sure what you meant, but it sounds like you are on the wrong track.
>> Let me explain...
>
> Thanks.
>
>>
>> The max_adj has nothing at all to do with the width of the time register.
>> Rather, it should reflect the maximum possible change in the tuning word.
>>
>> For example, with a nominal 8 ns period, the tuning word is 0x80000.
>> Looking at running the clock more slowly, the slowest possible word is
>> 0x00001, meaning a difference of 0x7FFFF. This implies an adjustment of
>> 0x7FFFF/0x80000 or 999998092 ppb. Running more quickly, we can already
>> have 0x100000, twice as fast, or just under 2 billion ppb.
>>
>> You should consider the extreme cases to determine the most limited
>> (smallest) max_adj value:
>>
>> Case 1 - high frequency
>> ~~~~~~~~~~~~~~~~~~~~~~~
>>
>> With a nominal 1 ns period, we have the nominal tuning word 0x10000.
>> The smallest is 0x1 for a difference of 0xFFFF. This corresponds to an
>> adjustment of 0xFFFF/0x10000 = .9999847412109375 or 999984741 ppb.
>>
>> Case 2 - low frequency
>> ~~~~~~~~~~~~~~~~~~~~~~
>>
>> With a nominal 255 ns period, the nominal word is 0xFF0000, the largest
>> 0xFFFFFF, and the difference is 0xFFFF. This corresponds to and adjustment
>> of 0xFFFF/0xFF0000 = .0039215087890625 or 3921508 ppb.
>>
>> Since 3921508 ppb is a huge adjustment, you can simply use that as a safe
>> maximum, ignoring the actual input clock.
>>
Thanks Richard.
So, if I understand right, this is theoretically limited by the
maximum input clock:
So if the highest frequency allowed (also commonly sourced in my case)
is 200MHz,
then with a 5ns time period, considering the adjustment to slowest
possible word,
0x4FFFF/0x50000 will be 999996948 ppb.
Shouldn't this be the max_adj?
I'm afraid I don't get why we are choosing the most limited max adj..
Sorry if I'm missing something - could you please help me understand?
Regards,
Harini
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