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Message-ID: <alpine.DEB.2.10.1702061334260.3301@vshiva-Udesk>
Date: Mon, 6 Feb 2017 13:36:47 -0800 (PST)
From: Shivappa Vikas <vikas.shivappa@...el.com>
To: "Luck, Tony" <tony.luck@...el.com>
cc: David Carrillo-Cisneros <davidcc@...gle.com>,
Thomas Gleixner <tglx@...utronix.de>,
Vikas Shivappa <vikas.shivappa@...ux.intel.com>,
"Shivappa, Vikas" <vikas.shivappa@...el.com>,
Stephane Eranian <eranian@...gle.com>,
linux-kernel <linux-kernel@...r.kernel.org>,
x86 <x86@...nel.org>, "hpa@...or.com" <hpa@...or.com>,
Ingo Molnar <mingo@...nel.org>,
Peter Zijlstra <peterz@...radead.org>,
"Shankar, Ravi V" <ravi.v.shankar@...el.com>,
"Yu, Fenghua" <fenghua.yu@...el.com>,
"Kleen, Andi" <andi.kleen@...el.com>,
"Anvin, H Peter" <h.peter.anvin@...el.com>
Subject: RE: [PATCH 00/12] Cqm2: Intel Cache quality monitoring fixes
On Mon, 6 Feb 2017, Luck, Tony wrote:
>> 12) Whatever fs or syscall is provided instead of perf syscalls, it
>> should provide total_time_enabled in the way perf does, otherwise is
>> hard to interpret MBM values.
>
> It seems that it is hard to define what we even mean by memory bandwidth.
>
> If you are measuring just one task and you find that the total number of bytes
> read is 1GB at some point, and one second later the total bytes is 2GB, then
> it is clear that the average bandwidth for this process is 1GB/s. If you know
> that the task was only running for 50% of the cycles during that 1s interval,
> you could say that it is doing 2GB/s ... which is I believe what you were
> thinking when you wrote #12 above. But whether that is right depends a
> bit on *why* it only ran 50% of the time. If it was time-sliced out by the
> scheduler ... then it may have been trying to be a 2GB/s app. But if it
> was waiting for packets from the network, then it really is using 1 GB/s.
Is the requirement is to have both enabled and run time or just enabled time
(enabled time must be easy to report - just the wall time from start trace to
end trace)?
This is not reported correctly in the upstream perf cqm and for
cgroup -C we dont report it either (since we report the package).
Thanks,
Vikas
>
> All bets are off if you are measuring a service that consists of several
> tasks running concurrently. All you can really talk about is the aggregate
> average bandwidth (total bytes / wall-clock time). It makes no sense to
> try and factor in how much cpu time each of the individual tasks got.
>
> -Tony
>
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