linux-kernel - Re: [PATCH -mm -v3] mm, swap: Sort swap entries before free

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Message-ID: <1492817351.3209.56.camel@linux.intel.com>
Date:   Fri, 21 Apr 2017 16:29:11 -0700
From:   Tim Chen <tim.c.chen@...ux.intel.com>
To:     "Huang, Ying" <ying.huang@...el.com>
Cc:     Minchan Kim <minchan@...nel.org>,
        Andrew Morton <akpm@...ux-foundation.org>, linux-mm@...ck.org,
        linux-kernel@...r.kernel.org, Hugh Dickins <hughd@...gle.com>,
        Shaohua Li <shli@...nel.org>, Rik van Riel <riel@...hat.com>
Subject: Re: [PATCH -mm -v3] mm, swap: Sort swap entries before free

On Fri, 2017-04-21 at 20:29 +0800, Huang, Ying wrote:
> "Huang, Ying" <ying.huang@...el.com> writes:
> 
> > 
> > Minchan Kim <minchan@...nel.org> writes:
> > 
> > > 
> > > On Wed, Apr 19, 2017 at 04:14:43PM +0800, Huang, Ying wrote:
> > > > 
> > > > Minchan Kim <minchan@...nel.org> writes:
> > > > 
> > > > > 
> > > > > Hi Huang,
> > > > > 
> > > > > On Fri, Apr 07, 2017 at 02:49:01PM +0800, Huang, Ying wrote:
> > > > > > 
> > > > > > From: Huang Ying <ying.huang@...el.com>
> > > > > > 
> > > > > >  void swapcache_free_entries(swp_entry_t *entries, int n)
> > > > > >  {
> > > > > >  	struct swap_info_struct *p, *prev;
> > > > > > @@ -1075,6 +1083,10 @@ void swapcache_free_entries(swp_entry_t *entries, int n)
> > > > > >  
> > > > > >  	prev = NULL;
> > > > > >  	p = NULL;
> > > > > > +
> > > > > > +	/* Sort swap entries by swap device, so each lock is only taken once. */
> > > > > > +	if (nr_swapfiles > 1)
> > > > > > +		sort(entries, n, sizeof(entries[0]), swp_entry_cmp, NULL);
> > > > > Let's think on other cases.
> > > > > 
> > > > > There are two swaps and they are configured by priority so a swap's usage
> > > > > would be zero unless other swap used up. In case of that, this sorting
> > > > > is pointless.
> > > > > 
> > > > > As well, nr_swapfiles is never decreased so if we enable multiple
> > > > > swaps and then disable until a swap is remained, this sorting is
> > > > > pointelss, too.
> > > > > 
> > > > > How about lazy sorting approach? IOW, if we found prev != p and,
> > > > > then we can sort it.
> > > > Yes.  That should be better.  I just don't know whether the added
> > > > complexity is necessary, given the array is short and sort is fast.
> > > Huh?
> > > 
> > > 1. swapon /dev/XXX1
> > > 2. swapon /dev/XXX2
> > > 3. swapoff /dev/XXX2
> > > 4. use only one swap
> > > 5. then, always pointless sort.
> > Yes.  In this situation we will do unnecessary sorting.  What I don't
> > know is whether the unnecessary sorting will hurt performance in real
> > life.  I can do some measurement.
> I tested the patch with 1 swap device and 1 process to eat memory
> (remove the "if (nr_swapfiles > 1)" for test).  

It is possible that nr_swapfiles > 1 when we have only 1 swapfile due
to swapoff.  The nr_swapfiles never decrement on swapoff.
We will need to use another counter in alloc_swap_info and
swapoff to track the true number of swapfiles in use to have a fast path
that avoid the search and sort for the 1 swap case.

Tim