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Message-ID: <20170425094927.GB16888@mai>
Date: Tue, 25 Apr 2017 11:49:27 +0200
From: Daniel Lezcano <daniel.lezcano@...aro.org>
To: Marc Zyngier <marc.zyngier@....com>
Cc: tglx@...utronix.de, Mark Rutland <mark.rutland@....com>,
Vineet Gupta <vgupta@...opsys.com>,
Patrice Chotard <patrice.chotard@...com>,
Kukjin Kim <kgene@...nel.org>,
Krzysztof Kozlowski <krzk@...nel.org>,
Javier Martinez Canillas <javier@....samsung.com>,
Christoffer Dall <christoffer.dall@...aro.org>,
Paolo Bonzini <pbonzini@...hat.com>,
Radim Krčmář <rkrcmar@...hat.com>,
linux-arm-kernel@...ts.infradead.org, linux-kernel@...r.kernel.org,
linux-snps-arc@...ts.infradead.org, kernel@...inux.com,
linux-samsung-soc@...r.kernel.org, kvmarm@...ts.cs.columbia.edu,
kvm@...r.kernel.org
Subject: Re: [PATCH V9 1/3] irq: Allow to pass the IRQF_TIMER flag with
percpu irq request
On Tue, Apr 25, 2017 at 10:10:12AM +0100, Marc Zyngier wrote:
[ ... ]
> >>>> Maybe you could explain why you think this interrupt is relevant to what
> >>>> you're trying to achieve?
> >>>
> >>> If this interrupt does not happen on the host, we don't care.
> >>
> >> All interrupts happen on the host. There is no such thing as a HW
> >> interrupt being directly delivered to a guest (at least so far). The
> >> timer is under control of the guest, which uses as it sees fit. When
> >> the HW timer expires, the interrupt fires on the host, which re-inject
> >> the interrupt in the guest.
> >
> > Ah, thanks for the clarification. Interesting.
> >
> > How can the host know which guest to re-inject the interrupt?
>
> The timer can only fire when the vcpu is running. If it is not running,
> a software timer is queued, with a pointer to the vcpu struct.
I see, thanks.
> >>> The flag IRQF_TIMER is used by the spurious irq handler in the try_one_irq()
> >>> function. However the per cpu timer interrupt will be discarded in the function
> >>> before because it is per cpu.
> >>
> >> Right. That's not because this is a timer, but because it is per-cpu.
> >> So why do we need this IRQF_TIMER flag, instead of fixing try_one_irq()?
> >
> > When a timer is not per cpu, (eg. request_irq), we need this flag, no?
>
> Sure, but in this series, they all seem to be per-cpu.
I think I was unclear. We need to tag an interrupt with IRQS_TIMINGS to record
their occurences but discarding the timers interrupt. That is done by checking
against IRQF_TIMER when setting up an interrupt.
request_irq() has a flag parameter which has IRQF_TIMER set in case of the
timers. request_percpu_irq has no flag parameter, so it is not possible to
discard these interrupts as the IRQS_TIMINGS will be set.
I don't understand how this is related to the the try_one_irq() fix you are
proposing. Am I missing something?
Regarding your description below, the host has no control at all on the virtual
timer and is not able to know the next expiration time, so I don't see the
point to add the IRQF_TIMER flag to the virtual timer.
I will resend a new version without this change on the virtual timer.
> >>> IMO, for consistency reason, adding the IRQF_TIMER makes sense. Other than
> >>> that, as the interrupt is not happening on the host, this flag won't be used.
> >>>
> >>> Do you want to drop this change?
> >>
> >> No, I'd like to understand the above. Why isn't the following patch
> >> doing the right thing?
> >
> > Actually, the explanation is in the next patch of the series (2/3)
> >
> > [ ... ]
> >
> > +static inline void setup_timings(struct irq_desc *desc, struct irqaction *act)
> > +{
> > + /*
> > + * We don't need the measurement because the idle code already
> > + * knows the next expiry event.
> > + */
> > + if (act->flags & __IRQF_TIMER)
> > + return;
>
> And that's where this is really wrong for the KVM guest timer. As I
> said, this timer is under complete control of the guest, and the rest of
> the system doesn't know about it. KVM itself will only find out when the
> vcpu does a VM exit for a reason or another, and will just save/restore
> the state in order to be able to give the timer to another guest.
>
> The idle code is very much *not* aware of anything concerning that guest
> timer.
Just for my own curiosity, if there are two VM (VM1 and VM2). VM1 sets a timer1
at <time> and exits, VM2 runs and sets a timer2 at <time+delta>.
The timer1 for VM1 is supposed to expire while VM2 is running. IIUC the virtual
timer is under control of VM2 and will expire at <time+delta>.
Is the host wake up with the SW timer and switch in VM1 which in turn restores
the timer and jump in the virtual timer irq handler?
> > +
> > + desc->istate |= IRQS_TIMINGS;
> > +}
> >
> > [ ... ]
> >
> > +/*
> > + * The function record_irq_time is only called in one place in the
> > + * interrupts handler. We want this function always inline so the code
> > + * inside is embedded in the function and the static key branching
> > + * code can act at the higher level. Without the explicit
> > + * __always_inline we can end up with a function call and a small
> > + * overhead in the hotpath for nothing.
> > + */
> > +static __always_inline void record_irq_time(struct irq_desc *desc)
> > +{
> > + if (!static_branch_likely(&irq_timing_enabled))
> > + return;
> > +
> > + if (desc->istate & IRQS_TIMINGS) {
> > + struct irq_timings *timings = this_cpu_ptr(&irq_timings);
> > +
> > + timings->values[timings->count & IRQ_TIMINGS_MASK] =
> > + irq_timing_encode(local_clock(),
> > + irq_desc_get_irq(desc));
> > +
> > + timings->count++;
> > + }
> > +}
> >
> > [ ... ]
> >
> > The purpose is to predict the next event interrupts on the system which are
> > source of wake up. For now, this patchset is focused on interrupts (discarding
> > timer interrupts).
> >
> > The following article gives more details: https://lwn.net/Articles/673641/
> >
> > When the interrupt is setup, we tag it except if it is a timer. So with this
> > patch there is another usage of the IRQF_TIMER where we will be ignoring
> > interrupt coming from a timer.
> >
> > As the timer interrupt is delivered to the host, we should not measure it as it
> > is a timer and set this flag.
> >
> > The needed information is: "what is the earliest VM timer?". If this
> > information is already available then there is nothing more to do, otherwise we
> > should add it in the future.
>
> This information is not readily available. You can only find it when it
> is too late (timer has already fired) or when it is not relevant anymore
> (guest is sleeping and we've queued a SW timer for it).
>
> Thanks,
>
> M.
> --
> Jazz is not dead. It just smells funny...
--
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