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Message-ID: <f15b2461-2502-4c60-e373-472d51dcaa83@linux.intel.com>
Date: Mon, 7 Aug 2017 18:22:59 +0300
From: Alexey Budankov <alexey.budankov@...ux.intel.com>
To: Peter Zijlstra <peterz@...radead.org>
Cc: Ingo Molnar <mingo@...hat.com>,
Arnaldo Carvalho de Melo <acme@...nel.org>,
Alexander Shishkin <alexander.shishkin@...ux.intel.com>,
Andi Kleen <ak@...ux.intel.com>,
Kan Liang <kan.liang@...el.com>,
Dmitri Prokhorov <Dmitry.Prohorov@...el.com>,
Valery Cherepennikov <valery.cherepennikov@...el.com>,
Mark Rutland <mark.rutland@....com>,
Stephane Eranian <eranian@...gle.com>,
David Carrillo-Cisneros <davidcc@...gle.com>,
linux-kernel <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH v6 1/3] perf/core: use rb trees for pinned/flexible groups
On 04.08.2017 17:53, Peter Zijlstra wrote:
> On Thu, Aug 03, 2017 at 11:30:09PM +0300, Alexey Budankov wrote:
>> On 03.08.2017 16:00, Peter Zijlstra wrote:
>>> On Wed, Aug 02, 2017 at 11:13:54AM +0300, Alexey Budankov wrote:
>
>>>> @@ -2759,13 +2932,13 @@ static void ctx_sched_out(struct perf_event_context *ctx,
>>>>
>>>> perf_pmu_disable(ctx->pmu);
>>>> if (is_active & EVENT_PINNED) {
>>>> - list_for_each_entry(event, &ctx->pinned_groups, group_entry)
>>>> - group_sched_out(event, cpuctx, ctx);
>>>> + perf_event_groups_iterate(&ctx->pinned_groups,
>>>> + group_sched_out_callback, ¶ms);
>>>
>>> So here I would expect to not iterate events where event->cpu !=
>>> smp_processor_id() (and ideally not where event->pmu != ctx->pmu).
>>>
>>
>> We still need to iterate thru all groups on thread context switch in
>> and out as well as iterate thru cpu == -1 list (software events) additionally
>> to smp_processor_id() list from multiplexing timer interrupt handler.
>
> Well, just doing the @cpu=-1 and @cpu=this_cpu subtrees is less work
> than iterating _everything_, right?
Right. That is actually the aim of this whole patch set - to avoid iterating "_everything_".
>
> The rest will not survive event_filter_match() anyway, so iterating them
> is complete waste of time, and once we have them in a tree, its actually
> easy to find this subset.
>
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