[<prev] [next>] [<thread-prev] [thread-next>] [day] [month] [year] [list]
Message-ID: <fa962d7c-2a6d-bb33-50b0-9d8f0057e8ab@linux.intel.com>
Date: Wed, 30 Aug 2017 11:30:26 +0300
From: Alexey Budankov <alexey.budankov@...ux.intel.com>
To: Alexander Shishkin <alexander.shishkin@...ux.intel.com>,
Peter Zijlstra <peterz@...radead.org>
Cc: Ingo Molnar <mingo@...hat.com>,
Arnaldo Carvalho de Melo <acme@...nel.org>,
Andi Kleen <ak@...ux.intel.com>,
Kan Liang <kan.liang@...el.com>,
Dmitri Prokhorov <Dmitry.Prohorov@...el.com>,
Valery Cherepennikov <valery.cherepennikov@...el.com>,
Mark Rutland <mark.rutland@....com>,
Stephane Eranian <eranian@...gle.com>,
David Carrillo-Cisneros <davidcc@...gle.com>,
linux-kernel <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH v6 1/3] perf/core: use rb trees for pinned/flexible groups
On 29.08.2017 16:51, Alexander Shishkin wrote:
> Alexey Budankov <alexey.budankov@...ux.intel.com> writes:
>
>> Now I figured that not all indexed events are always located under
>> the root with the same cpu, and it depends on the order of insertion
>> e.g. with insertion order 01,02,03,14,15,16 we get this:
>>
>> 02
>> / \
>> 01 14
>> / \
>> 03 15
>> \
>> 16
>>
>> and it is unclear how to iterate cpu==0 part of tree in this case.
>
> Using this example, rb_next() should take you through the nodes in this
> order (assuming you start with 01): 01, 02, 03, 14, etc. So you iterate
> while event->cpu==cpu using rb_next() and you should be fine.
Well, indeed we get the most left leaf (03) in rb_next() for the case above.
>
>> Iterating cpu specific subtree like this:
>>
>> #define for_each_group_event(event, group, cpu, pmu, field) \
>> for (event = rb_entry_safe(group_first(group, cpu, pmu), \
>> typeof(*event), field); \
>> event && event->cpu == cpu && event->pmu == pmu; \
>> event = rb_entry_safe(rb_next(&event->field), \
>> typeof(*event), field))
>
> Afaict, this assumes that you are also ordering on event->pmu, which
> should be reflected in your _less function. And also assuming that
> group_first() is doing the right thing. Can we see the code?
I didn't do ordering by PMU for this patch set. Yet more I implemented
groups_first() like this:
static struct perf_event *
perf_event_groups_first(struct perf_event_groups *groups, int cpu)
{
struct perf_event *node_event = NULL;
struct rb_node *node = NULL;
node = groups->tree.rb_node;
while (node) {
node_event = container_of(node,
struct perf_event, group_node);
if (cpu < node_event->cpu) {
node = node->rb_left;
} else if (cpu > node_event->cpu) {
node = node->rb_right;
} else {
node = node->rb_left;
}
}
return node_event;
}
and it doesn't work as expected for case above with cpu == 1.
I corrected the code above to this:
static struct perf_event *
perf_event_groups_first(struct perf_event_groups *groups, int cpu)
{
struct perf_event *node_event = NULL, *match = NULL;
struct rb_node *node = NULL;
node = groups->tree.rb_node;
while (node) {
node_event = container_of(node,
struct perf_event, group_node);
if (cpu < node_event->cpu) {
node = node->rb_left;
} else if (cpu > node_event->cpu) {
node = node->rb_right;
} else {
match = node_event;
node = node->rb_left;
}
}
return match;
}
but now struggling with silent oopses which I guess are not
related to multiplexing at all.
Please look at v8 for a while. It addresses your comments for v7.
>
> Regards,
> --
> Alex
>
Thanks,
Alexey
Powered by blists - more mailing lists