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Message-ID: <20171116011906.GE6280@tardis>
Date: Thu, 16 Nov 2017 09:19:06 +0800
From: Boqun Feng <boqun.feng@...il.com>
To: Daniel Lustig <dlustig@...dia.com>
Cc: Palmer Dabbelt <palmer@...belt.com>,
"will.deacon@....com" <will.deacon@....com>,
Arnd Bergmann <arnd@...db.de>, Olof Johansson <olof@...om.net>,
"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
"patches@...ups.riscv.org" <patches@...ups.riscv.org>,
"peterz@...radead.org" <peterz@...radead.org>
Subject: Re: [patches] Re: [PATCH v9 05/12] RISC-V: Atomic and Locking Code
On Wed, Nov 15, 2017 at 11:59:44PM +0000, Daniel Lustig wrote:
> > On Wed, 15 Nov 2017 10:06:01 PST (-0800), will.deacon@....com wrote:
> >> On Tue, Nov 14, 2017 at 12:30:59PM -0800, Palmer Dabbelt wrote:
> >> > On Tue, 24 Oct 2017 07:10:33 PDT (-0700), will.deacon@....com wrote:
> >> >>On Tue, Sep 26, 2017 at 06:56:31PM -0700, Palmer Dabbelt wrote:
> > >
> > > Hi Palmer,
> > >
> > >> >>+ATOMIC_OPS(add, add, +, i, , _relaxed)
> > >> >>+ATOMIC_OPS(add, add, +, i, .aq , _acquire) ATOMIC_OPS(add, add,
> > >> >>++, i, .rl , _release)
> > >> >>+ATOMIC_OPS(add, add, +, i, .aqrl, )
> > >> >
> > >> >Have you checked that .aqrl is equivalent to "ordered", since there
> > >> >are interpretations where that isn't the case. Specifically:
> > >> >
> > >> >// all variables zero at start of time
> > >> >P0:
> > >> >WRITE_ONCE(x) = 1;
> > >> >atomic_add_return(y, 1);
> > >> >WRITE_ONCE(z) = 1;
> > >> >
> > >> >P1:
> > >> >READ_ONCE(z) // reads 1
> > >> >smp_rmb();
> > >> >READ_ONCE(x) // must not read 0
> > >>
> > >> I haven't. We don't quite have a formal memory model specification yet.
> > >> I've added Daniel Lustig, who is creating that model. He should have
> > >> a better idea
> > >
> > > Thanks. You really do need to ensure that, as it's heavily relied upon.
> >
> > I know it's the case for our current processors, and I'm pretty sure it's the
> > case for what's formally specified, but we'll have to wait for the spec in order
> > to prove it.
>
> I think Will is right. In the current spec, using .aqrl converts an RCpc load
> or store into an RCsc load or store, but the acquire(-RCsc) annotation still
> only applies to the load part of the atomic, and the release(-RCsc) annotation
> applies only to the store part of the atomic.
>
> Why is that? Picture an machine which implements AMOs using something that
> looks more like an LR/SC under the covers, or one that uses cache line locking,
> or anything else along those same lines. In some such machines, there could be
> a window between lock/reserve and unlock/store-conditional where other later
> stores could squeeze into, and that would break Will's example among others.
>
> It's likely the same reasoning that causes ARM to use a trailing dmb here,
> rather than just using ldaxr/stlxr. Is that right Will? I know that's LL/SC
> and this particular cases uses AMOADD, but it's the same principle. Well, at
> least according to how we have it in the current memory model draft.
>
> Also, RISC-V currently prefers leading fence mappings, so I think the result
> here, for atomic_add_return() for example, should be this:
>
> fence rw,rw
> amoadd.aq ...
>
Hmm.. if atomic_add_return() is implemented like that, how about the
following case:
{x=0, y=0}
P1:
r1 = atomic_add_return(&x, 1); // r1 == 0, x will 1 afterwards
WRITE_ONCE(y, 1);
P2:
r2 = READ_ONCE(y); // r2 = 1
smp_rmb();
r3 = atomic_read(&x); // r3 = 0?
, could this result in r1 == 1 && r2 == 1 && r3 == 0? Given you said .aq
only effects the load part of AMO, and I don't see anything here
preventing the reordering between store of y and the store part of the
AMO on P1.
Note: we don't allow (r1 == 1 && r2 == 1 && r3 == 0) in above case for
linux kernel. Please see Documentation/atomic_t.txt:
"Fully ordered primitives are ordered against everything prior and
everything subsequent. Therefore a fully ordered primitive is like
having an smp_mb() before and an smp_mb() after the primitive."
Regards,
Boqun
> Note that at this point, I think you could even elide the .rl. If I'm reading
> it right it looks like the ARM mapping does this too (well, the reverse: ARM
> elides the "a" in ldaxr due to the trailing dmb making it redundant).
>
> Does that seem reasonable to you all?
>
> Dan
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