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Message-ID: <5A3F57D0.9050007@intel.com>
Date: Sun, 24 Dec 2017 15:31:28 +0800
From: Wei Wang <wei.w.wang@...el.com>
To: Tetsuo Handa <penguin-kernel@...ove.SAKURA.ne.jp>,
willy@...radead.org
CC: virtio-dev@...ts.oasis-open.org, linux-kernel@...r.kernel.org,
qemu-devel@...gnu.org, virtualization@...ts.linux-foundation.org,
kvm@...r.kernel.org, linux-mm@...ck.org, mst@...hat.com,
mhocko@...nel.org, akpm@...ux-foundation.org,
mawilcox@...rosoft.com
Subject: Re: [PATCH v20 3/7 RESEND] xbitmap: add more operations
On 12/23/2017 10:33 PM, Tetsuo Handa wrote:
>>>> + bitmap = rcu_dereference_raw(*slot);
>>>> + if (!bitmap) {
>>>> + bitmap = this_cpu_xchg(ida_bitmap, NULL);
>>>> + if (!bitmap)
>>>> + return -ENOMEM;
>>> I can't understand this. I can understand if it were
>>>
>>> BUG_ON(!bitmap);
>>>
>>> because you called xb_preload().
>>>
>>> But
>>>
>>> /*
>>> * Regular test 2
>>> * set bit 2000, 2001, 2040
>>> * Next 1 in [0, 2048) --> 2000
>>> * Next 1 in [2000, 2002) --> 2000
>>> * Next 1 in [2002, 2041) --> 2040
>>> * Next 1 in [2002, 2040) --> none
>>> * Next 0 in [2000, 2048) --> 2002
>>> * Next 0 in [2048, 2060) --> 2048
>>> */
>>> xb_preload(GFP_KERNEL);
>>> assert(!xb_set_bit(&xb1, 2000));
>>> assert(!xb_set_bit(&xb1, 2001));
>>> assert(!xb_set_bit(&xb1, 2040));
>> [...]
>>> xb_preload_end();
>>>
>>> you are not calling xb_preload() prior to each xb_set_bit() call.
>>> This means that, if each xb_set_bit() is not surrounded with
>>> xb_preload()/xb_preload_end(), there is possibility of hitting
>>> this_cpu_xchg(ida_bitmap, NULL) == NULL.
>> This is just a lazy test. We "know" that the bits in the range 1024-2047
>> will all land in the same bitmap, so there's no need to preload for each
>> of them.
> Testcases also serves as how to use that API.
> Assuming such thing leads to incorrect usage.
If callers are aware that the bits that they going to record locate in
the same bitmap, I think they should also perform the xb_ APIs with only
one preload. So the test cases here have shown them a correct example.
We can probably add some comments above to explain this.
Best,
Wei
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