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Message-ID: <20180222163120.zhytq7yezny4e7mj@tardis>
Date: Fri, 23 Feb 2018 00:31:20 +0800
From: Boqun Feng <boqun.feng@...il.com>
To: Peter Zijlstra <peterz@...radead.org>
Cc: linux-kernel@...r.kernel.org, Ingo Molnar <mingo@...hat.com>,
Andrea Parri <parri.andrea@...il.com>
Subject: Re: [RFC tip/locking/lockdep v5 05/17] lockdep: Extend __bfs() to
work with multiple kinds of dependencies
On Thu, Feb 22, 2018 at 04:51:43PM +0100, Peter Zijlstra wrote:
> On Thu, Feb 22, 2018 at 04:30:34PM +0100, Peter Zijlstra wrote:
> > On Thu, Feb 22, 2018 at 11:12:10PM +0800, Boqun Feng wrote:
> > > On Thu, Feb 22, 2018 at 03:26:14PM +0100, Peter Zijlstra wrote:
> >
> > > > However, I would suggest:
> > > >
> > > > static inline bool is_xr(u16 dep)
> > > > {
> > > > return !!(dep & (DEP_NR_MASK | DEP_RR_MASK));
> > > > }
> > > >
> > > > static inline bool is_rx(u16 dep)
> > > > {
> > > > return !!(dep & (DEP_RN_MASK | DEP_RR_MASK));
> > > > }
> > > >
> > > > /* Skip *R -> R* relations */
> > > > if (have_xr && is_rx(entry->dep))
> > > > continue;
> > >
> > > I don't think this works, if we pick a *R for previous entry, and for
> > > current entry, we have RR, NN and NR, your approach will skip the
> > > current entry, but actually we can pick NN or NR (of course, in __bfs(),
> > > we can greedily pick NN, because if NR causes a deadlock, so does NN).
> >
> > I don't get it, afaict my suggestion is identical.
> >
> > You skip condition: pick_dep() < 0, evaluates to:
> >
> > is_rr && (!NN_MASK && !NR_MASK) :=
> > is_rr && (RN_MASK | RR_MASK)
> >
> > Which is exactly what I have.
>
> Ooh, I think I see what I did wrong, would something like:
>
> if (have_xr && !is_nx(entry-dep))
>
> work? That's a lot harder to argue about though, still much better than
I think it works. Although I prefer use name "has_nx" for the fucntion.
> that tri-state pick thing.
>
Agree.
> > If that is satisfied, you set entry->is_rr to pick_dep(), which his
> > harder to evaluate, but is something like:
> >
> > is_rr && NR_MASK || !(NN_MASK | RN_MASK) :=
If is_rr is true and NN_MASK is true, pick_dep() will return 0, however,
your expression will return NR_MASK.
entry->have_xr = !(has_nn(entry->dep) || (!is_rr && has_rn(entry->dep)));
:= !has_nn(entry->dep) && (is_rr || !has_rn(entry->dep))
Regards,
Boqun
> > is_rr && NR_MASK || (NR_MASK | RR_MASK) :=
> > (NR_MASK | RR_MASK)
> >
> > (because is_rr && RR_MASK will have been skipped)
> >
> > > >
> > > > entry->have_xr = is_xr(entry->dep);
>
> This one I think is still correct though.
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