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Message-ID: <alpine.DEB.2.21.1806241411040.8650@nanos.tec.linutronix.de>
Date: Sun, 24 Jun 2018 14:12:49 +0200 (CEST)
From: Thomas Gleixner <tglx@...utronix.de>
To: Lukas Wunner <lukas@...ner.de>
cc: Bjorn Helgaas <bhelgaas@...gle.com>,
Mika Westerberg <mika.westerberg@...ux.intel.com>,
linux-kernel@...r.kernel.org, linux-pci@...r.kernel.org
Subject: Re: [PATCH v2 2/2] genirq: Synchronize only with single thread on
free_irq()
On Sun, 24 Jun 2018, Lukas Wunner wrote:
> On Sun, Jun 24, 2018 at 11:49:10AM +0200, Thomas Gleixner wrote:
> > On Sun, 24 Jun 2018, Lukas Wunner wrote:
> > > When pciehp is converted to threaded IRQ handling, removal of unplugged
> > > devices below a PCIe hotplug port happens synchronously in the IRQ
> > > thread. Removal of devices typically entails a call to free_irq() by
> > > their drivers.
> >
> > Is this an actual mainline problem or did you discover that in course of
> > upcoming work?
>
> It's needed for upcoming work, specifically the pciehp event handling
> rework which will hopefully appear in 4.19, so nothing urgent.
> Doesn't hurt at all to let this bake in linux-next for a few weeks.
Good.
> There is something else, you introduced irq_wake_thread() four years ago
> with a92444c6b222 for sdhci/sdio, but for some reason it was never used.
> Before you or anyone else deletes it for lack of callers, please be aware
> that I'm making heavy use of it now in pciehp.
Ha! I was looking at it yesterday for unrelated reasons and was wondering
about the huge amount of users ....
> I forgot to cc you on the relevant patch [17/32], but I'll bounce it to
> you in a minute in case you want to take a look at it.
Sure
> Of course this begs the question how irq_wake_thread() is serialized
> against __free_irq(), but it seems that's safe because irq_wake_thread()
> searches the action list while holding desc->lock: If it grabs the lock
> before __free_irq(), it'll just wake the thread normally. If it grabs
> the lock after __free_irq(), the action will be gone from the list,
> so irq_wake_thread() essentially becomes a no-op.
Exactly.
Thanks,
tglx
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