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Message-ID: <Pine.LNX.4.44L0.1807101127320.1449-100000@iolanthe.rowland.org>
Date: Tue, 10 Jul 2018 11:34:45 -0400 (EDT)
From: Alan Stern <stern@...land.harvard.edu>
To: Andrea Parri <andrea.parri@...rulasolutions.com>
cc: "Paul E. McKenney" <paulmck@...ux.vnet.ibm.com>,
LKMM Maintainers -- Akira Yokosawa <akiyks@...il.com>,
Boqun Feng <boqun.feng@...il.com>,
Daniel Lustig <dlustig@...dia.com>,
David Howells <dhowells@...hat.com>,
Jade Alglave <j.alglave@....ac.uk>,
Luc Maranget <luc.maranget@...ia.fr>,
Nicholas Piggin <npiggin@...il.com>,
Peter Zijlstra <peterz@...radead.org>,
Will Deacon <will.deacon@....com>,
Kernel development list <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH v2] tools/memory-model: Add extra ordering for locks and
remove it for ordinary release/acquire
On Tue, 10 Jul 2018, Andrea Parri wrote:
> > > ACQUIRE operations include LOCK operations and both smp_load_acquire()
> > > and smp_cond_acquire() operations. [BTW, the latter was replaced by
> > > smp_cond_load_acquire() in 1f03e8d2919270 ...]
> > >
> > > RELEASE operations include UNLOCK operations and smp_store_release()
> > > operations. [...]
> > >
> > > [...] after an ACQUIRE on a given variable, all memory accesses
> > > preceding any prior RELEASE on that same variable are guaranteed
> > > to be visible.
> >
> > As far as I can see, these statements remain valid.
>
> Interesting; ;-) What does these statement tells you ;-) when applied
> to a: and b: below?
>
> a: WRITE_ONCE(x, 1); // "preceding any prior RELEASE..."
> smp_store_release(&s, 1);
> smp_load_acquire(&s);
> b: WRITE_ONCE(y, 1); // "after an ACQUIRE..."
The first statement tells me that b: follows an ACQUIRE.
The second tells me that a: precedes a RELEASE.
And the third tells me that any READ_ONCE(x) statements coming po-after
b: would see x = 1 or a later value of x. (Of course, they would have
to see that anyway because of the cache coherency rules.)
More to the point, given:
P0()
{
WRITE_ONCE(x, 1);
a: smp_store_release(&s, 1);
}
P1()
{
b: r1 = smp_load_acquire(&s);
r2 = READ_ONCE(x);
}
the third statement tells me that if r1 = 1 (that is, if a: is prior to
b:) then r2 must be 1.
Alan
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