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Message-ID: <ca282523-5184-ae79-ecfc-5e6048562420@c-s.fr>
Date: Tue, 18 Sep 2018 13:53:33 +0200
From: Christophe LEROY <christophe.leroy@....fr>
To: "Aneesh Kumar K.V" <aneesh.kumar@...ux.ibm.com>,
akpm@...ux-foundation.org, linux-mm@...ck.org,
aneesh.kumar@...ux.vnet.ibm.com,
Nicholas Piggin <npiggin@...il.com>,
Michael Ellerman <mpe@...erman.id.au>,
linuxppc-dev@...ts.ozlabs.org
Cc: LKML <linux-kernel@...r.kernel.org>
Subject: Re: How to handle PTE tables with non contiguous entries ?
Le 18/09/2018 à 13:47, Aneesh Kumar K.V a écrit :
> Christophe LEROY <christophe.leroy@....fr> writes:
>
>> Le 17/09/2018 à 11:03, Aneesh Kumar K.V a écrit :
>>> Christophe Leroy <christophe.leroy@....fr> writes:
>>>
>>>> Hi,
>>>>
>>>> I'm having a hard time figuring out the best way to handle the following
>>>> situation:
>>>>
>>>> On the powerpc8xx, handling 16k size pages requires to have page tables
>>>> with 4 identical entries.
>>>
>>> I assume that hugetlb page size? If so isn't that similar to FSL hugetlb
>>> page table layout?
>>
>> No, it is not for 16k hugepage size with a standard page size of 4k.
>>
>> Here I'm trying to handle the case of CONFIG_PPC_16K_PAGES.
>> As of today, it is implemented by using the standard Linux page layout,
>> ie one PTE entry for each 16k page. This forbids the use the 8xx HW
>> assistance.
>>
>>>
>>>>
>>>> Initially I was thinking about handling this by simply modifying
>>>> pte_index() which changing pte_t type in order to have one entry every
>>>> 16 bytes, then replicate the PTE value at *ptep, *ptep+1,*ptep+2 and
>>>> *ptep+3 both in set_pte_at() and pte_update().
>>>>
>>>> However, this doesn't work because many many places in the mm core part
>>>> of the kernel use loops on ptep with single ptep++ increment.
>>>>
>>>> Therefore did it with the following hack:
>>>>
>>>> /* PTE level */
>>>> +#if defined(CONFIG_PPC_8xx) && defined(CONFIG_PPC_16K_PAGES)
>>>> +typedef struct { pte_basic_t pte, pte1, pte2, pte3; } pte_t;
>>>> +#else
>>>> typedef struct { pte_basic_t pte; } pte_t;
>>>> +#endif
>>>>
>>>> @@ -181,7 +192,13 @@ static inline unsigned long pte_update(pte_t *p,
>>>> : "cc" );
>>>> #else /* PTE_ATOMIC_UPDATES */
>>>> unsigned long old = pte_val(*p);
>>>> - *p = __pte((old & ~clr) | set);
>>>> + unsigned long new = (old & ~clr) | set;
>>>> +
>>>> +#if defined(CONFIG_PPC_8xx) && defined(CONFIG_PPC_16K_PAGES)
>>>> + p->pte = p->pte1 = p->pte2 = p->pte3 = new;
>>>> +#else
>>>> + *p = __pte(new);
>>>> +#endif
>>>> #endif /* !PTE_ATOMIC_UPDATES */
>>>>
>>>> #ifdef CONFIG_44x
>>>>
>>>>
>>>> @@ -161,7 +161,11 @@ static inline void __set_pte_at(struct mm_struct
>>>> *mm, unsigned long addr,
>>>> /* Anything else just stores the PTE normally. That covers all
>>>> 64-bit
>>>> * cases, and 32-bit non-hash with 32-bit PTEs.
>>>> */
>>>> +#if defined(CONFIG_PPC_8xx) && defined(CONFIG_PPC_16K_PAGES)
>>>> + ptep->pte = ptep->pte1 = ptep->pte2 = ptep->pte3 = pte_val(pte);
>>>> +#else
>>>> *ptep = pte;
>>>> +#endif
>>>>
>>>>
>>>>
>>>> But I'm not too happy with it as it means pte_t is not a single type
>>>> anymore so passing it from one function to the other is quite heavy.
>>>>
>>>>
>>>> Would someone have an idea of an elegent way to handle that ?
>>>>
>>>> Thanks
>>>> Christophe
>>>
>>> Why would pte_update bother about updating all the 4 entries?. Can you
>>> help me understand the issue?
>>
>> Because the 8xx HW assistance expects 4 identical entries for each 16k
>> page, so everytime a PTE is updated the 4 entries have to be updated.
>>
>
> What you suggested in the original mail is what matches that best isn't it?
> That is a linux pte update involves updating 4 slot. Hence a linux pte
> consist of 4 unsigned long?
>
Yes indeed.
It seems hopeless to avoid carrying the 4 longs from one function to the
other allthough that's four times the same thing.
Christophe
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