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Message-ID: <1550092329.6911.35.camel@lca.pw>
Date: Wed, 13 Feb 2019 16:12:09 -0500
From: Qian Cai <cai@....pw>
To: Andrey Konovalov <andreyknvl@...gle.com>
Cc: Andrew Morton <akpm@...ux-foundation.org>,
Christoph Lameter <cl@...ux.com>,
Pekka Enberg <penberg@...nel.org>,
David Rientjes <rientjes@...gle.com>,
Joonsoo Kim <iamjoonsoo.kim@....com>,
Linux Memory Management List <linux-mm@...ck.org>,
LKML <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH] slub: untag object before slab end
On Wed, 2019-02-13 at 11:31 +0100, Andrey Konovalov wrote:
> On Wed, Feb 13, 2019 at 3:06 AM Qian Cai <cai@....pw> wrote:
> >
> > get_freepointer() could return NULL if there is no more free objects in
> > the slab. However, it could return a tagged pointer (like
> > 0x2200000000000000) with KASAN_SW_TAGS which would escape the NULL
> > object checking in check_valid_pointer() and trigger errors below, so
> > untag the object before checking for a NULL object there.
>
> I think this solution is just masking the issue. get_freepointer()
> shouldn't return tagged NULLs. Apparently when we save a freelist
> pointer, the object where the pointer gets written is tagged
> differently, than this same object when the pointer gets read. I found
> one case where this happens (the last patch out my 5 patch series),
> but apparently there are more.
Well, the problem is that,
__free_slab
for_each_object(p, s, page_address(page) [1]
check_object(s, page, p ...)
get_freepointer(s, p)
[1]: p += s->size
page_address() tags the address using page_kasan_tag(page), so each "p" here has
that tag.
However, at beginning in allocate_slab(), it tags each object with a random tag,
and then calls set_freepointer(s, p, NULL)
As the result, get_freepointer() returns a tagged NULL because it never be able
to obtain the original tag of the object anymore, and this calculation is now
wrong.
return (void *)((unsigned long)ptr ^ s->random ^ ptr_addr);
This also explain why this patch also works, as it unifies the tags.
https://marc.info/?l=linux-mm&m=154955366113951&w=2
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