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Message-ID: <20190304184708.GQ32494@hirez.programming.kicks-ass.net>
Date: Mon, 4 Mar 2019 19:47:08 +0100
From: Peter Zijlstra <peterz@...radead.org>
To: Quentin Perret <quentin.perret@....com>
Cc: Wang, Vincent (王争)
<Vincent.Wang@...soc.com>,
Zhang, Chunyan (张春艳)
<Chunyan.Zhang@...soc.com>, Ingo Molnar <mingo@...hat.com>,
"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
Chunyan Zhang <zhang.lyra@...il.com>,
"Rafael J. Wysocki" <rjw@...ysocki.net>
Subject: Re: 答复: [PATCH V4] sched/cpufreq: initialize iowait_boost_max and
iowait_boost with cpu capacity
On Mon, Mar 04, 2019 at 05:50:32PM +0000, Quentin Perret wrote:
> On Monday 04 Mar 2019 at 18:40:28 (+0100), Peter Zijlstra wrote:
> > > Perhaps you could keep the 'util' and 'max' pointers in
> > > sugov_iowait_apply() and overwrite them like before, but in the
> > > SCHED_CAPACITY_SCALE scale as you suggest ?
> >
> > Urgh; but then we're back to having that boostrap problem.
>
> Hmm, I don't understand :/
Yeah, I seen to have reading comprehension issues today. Ignore that.
> > Now; at this time; @max is in fact scale_cpu_capacity, so can't we
> > change this:
> >
> > - /*
> > - * Apply the current boost value: a CPU is boosted only if its current
> > - * utilization is smaller then the current IO boost level.
> > - */
> > - boost_util = sg_cpu->iowait_boost;
> > - boost_max = sg_cpu->iowait_boost_max;
>
> I was basically suggesting to do 'boost_max = 1024;' here and you
> should be good with you way of computing 'min' no ?
Right, but then we keep having to retain those two mults.
> > - if (*util * boost_max < *max * boost_util) {
> > - *util = boost_util;
> > - *max = boost_max;
> > - }
> > + sg_cpu->iowait_boost_pending = false;
> > +
> > + return min(max(util, sg_cpu->iowait_boost), max);
> > }
> >
> > to something like:
> >
> > /*
> > * @util is already in capacity scale, convert iowait_boost
> > * into the same scale so we can compare.
> > */
> > boost = (sg_cpu->iowait_boost * max) >> SCHED_CAPACITY_SHIFT;
> > util = max(boost, util);
> > return min(util, max);
> >
>
> But this should work too, I think.
While that is only a single mult.
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