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Message-ID: <20190322015208.GD19508@bombadil.infradead.org>
Date: Thu, 21 Mar 2019 18:52:08 -0700
From: Matthew Wilcox <willy@...radead.org>
To: Waiman Long <longman@...hat.com>
Cc: Andrew Morton <akpm@...ux-foundation.org>,
Christoph Lameter <cl@...ux.com>,
Pekka Enberg <penberg@...nel.org>,
David Rientjes <rientjes@...gle.com>,
Joonsoo Kim <iamjoonsoo.kim@....com>,
linux-kernel@...r.kernel.org, linux-mm@...ck.org,
selinux@...r.kernel.org, Paul Moore <paul@...l-moore.com>,
Stephen Smalley <sds@...ho.nsa.gov>,
Eric Paris <eparis@...isplace.org>,
"Peter Zijlstra (Intel)" <peterz@...radead.org>,
Oleg Nesterov <oleg@...hat.com>
Subject: Re: [PATCH 2/4] signal: Make flush_sigqueue() use free_q to release
memory
On Thu, Mar 21, 2019 at 05:45:10PM -0400, Waiman Long wrote:
> It was found that if a process had many pending signals (e.g. millions),
> the act of exiting that process might cause its parent to have a hard
> lockup especially on a debug kernel with features like KASAN enabled.
> It was because the flush_sigqueue() was called in release_task() with
> tasklist_lock held and irq disabled.
This rather apocalyptic language is a bit uncalled for. I appreciate the
warning is scary, but all that's really happening is that the debug code
is taking too long to execute.
> To avoid this dire condition and reduce lock hold time of tasklist_lock,
> flush_sigqueue() is modified to pass in a freeing queue pointer so that
> the actual freeing of memory objects can be deferred until after the
> tasklist_lock is released and irq re-enabled.
I think this is a really bad solution. It looks kind of generic,
but isn't. It's terribly inefficient, and all it's really doing is
deferring the debugging code until we've re-enabled interrupts.
We'd be much better off just having a list_head in the caller
and list_splice() the queue->list onto that caller. Then call
__sigqueue_free() for each signal on the queue.
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