[<prev] [next>] [<thread-prev] [thread-next>] [day] [month] [year] [list]
Message-ID: <5614f04f-827d-1668-9ed0-60d93e110b8e@codeaurora.org>
Date: Wed, 24 Apr 2019 17:40:40 +0530
From: Mukesh Ojha <mojha@...eaurora.org>
To: Al Viro <viro@...iv.linux.org.uk>,
"dmitry.torokhov@...il.com" <dmitry.torokhov@...il.com>
Cc: linux-input@...r.kernel.org, linux-kernel@...r.kernel.org,
Gaurav Kohli <gkohli@...eaurora.org>,
Peter Hutterer <peter.hutterer@...-t.net>,
Martin Kepplinger <martink@...teo.de>,
"Paul E. McKenney" <paulmck@...ux.ibm.com>
Subject: Re: [PATCH v2] Input: uinput: Avoid Object-Already-Free with a global
lock
On 4/23/2019 4:36 PM, Al Viro wrote:
> On Tue, Apr 23, 2019 at 08:49:44AM +0000, dmitry.torokhov@...il.com wrote:
>> On Tue, Apr 23, 2019 at 12:51:13PM +0530, Mukesh Ojha wrote:
>>> I have taken care this case from ioctl and release point of view.
>>>
>>> Even if the release gets called first it will make the
>>> file->private_data=NULL.
>>> and further call to ioctl will not be a problem as the check is already
>>> there.
>> Al, do we have any protections in VFS layer from userspace hanging onto
>> a file descriptor and calling ioctl() on it even as another thread
>> calls close() on the same fd?
>>
>> Should the issue be solved by individual drivers, or more careful
>> accounting for currently running operations is needed at VFS layer?
> Neither. An overlap of ->release() and ->ioctl() is possible only
> if you've got memory corruption somewhere.
>
> close() overlapping ioctl() is certainly possible, and won't trigger
> that at all - sys_ioctl() holds onto reference to struct file, so
> its refcount won't reach zero until we are done with it.
Al,
i tried to put traceprintk inside ioctl after fdget and fdput on a
simple call of open => ioctl => close
on /dev/uinput.
uinput-532 [002] .... 45.312044: SYSC_ioctl: 2 <=
f_count > <After fdget()
uinput-532 [002] .... 45.312055: SYSC_ioctl:
2 <After fdput()
uinput-532 [004] .... 45.313766: uinput_open: uinput: 1
uinput-532 [004] .... 45.313783: SYSC_ioctl: 1
uinput-532 [004] .... 45.313788: uinput_ioctl_handler:
uinput: uinput_ioctl_handler, 1
uinput-532 [004] .... 45.313835: SYSC_ioctl: 1
uinput-532 [004] .... 45.313843: uinput_release: uinput: 0
So while a ioctl is running the f_count is 1, so a fput could be run and
do atomic_long_dec_and_test
this could call release right ?
-Mukesh
Powered by blists - more mailing lists