linux-kernel - Re: [PATCH] tun: Fix use-after-free in tun_net

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Message-ID: <CAM_iQpXbQ4X+ohmNFy79D+MPu6remA7hU0DTTypS=Yt+BCxujA@mail.gmail.com>
Date:   Tue, 30 Apr 2019 16:42:31 -0700
From:   Cong Wang <xiyou.wangcong@...il.com>
To:     "weiyongjun (A)" <weiyongjun1@...wei.com>
Cc:     "Michael S. Tsirkin" <mst@...hat.com>,
        yuehaibing <yuehaibing@...wei.com>,
        David Miller <davem@...emloft.net>,
        Jason Wang <jasowang@...hat.com>,
        Eric Dumazet <edumazet@...gle.com>,
        Jesper Dangaard Brouer <brouer@...hat.com>,
        "Li,Rongqing" <lirongqing@...du.com>,
        Nicolas Dichtel <nicolas.dichtel@...nd.com>,
        Chas Williams <3chas3@...il.com>,
        "wangli39@...du.com" <wangli39@...du.com>,
        LKML <linux-kernel@...r.kernel.org>,
        Linux Kernel Network Developers <netdev@...r.kernel.org>
Subject: Re: [PATCH] tun: Fix use-after-free in tun_net_xmit

On Mon, Apr 29, 2019 at 10:11 PM weiyongjun (A) <weiyongjun1@...wei.com> wrote:
> This patch should not work. The key point is that when detach the queue
> with index is equal to tun->numqueues - 1, we do not clear the point
> in tun->tfiles:
>
> static void __tun_detach(...)
> {
> ...
>         **** if index == tun->numqueues - 1, nothing changed ****
>         rcu_assign_pointer(tun->tfiles[index],
>                                                 tun->tfiles[tun->numqueues - 1]);
> ....
> }


This is _perfectly_ fine. This is just how we _unpublish_ it, RCU is NOT
against unpublish, you keep missing this point.

Think about list_del_rcu(). RCU readers could still read the list entry
even _after_ list_del_rcu(), this is perfectly fine, list_del_rcu() just
unpublishes the list entry from a global list, kfree_rcu() is the one frees
it. So, RCU readers never hate "unpublish", they just hate "free".


>
> And after tfile free, xmit have change to get and use the freed file point.

With SOCK_RCU_FREE, it won't be freed until the last reader is gone.
This is the fundamental of RCU.

Please, at least look into sk_destruct().

Thanks.