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Message-ID: <1830378.zUSKOufHgj@phil>
Date:   Thu, 09 May 2019 10:45:56 +0200
From:   Heiko Stuebner <heiko@...ech.de>
To:     Douglas Anderson <dianders@...omium.org>
Cc:     Stephen Boyd <sboyd@...nel.org>,
        Shawn Lin <shawn.lin@...k-chips.com>, hal@...emmerich.com,
        amstan@...omium.org, Michael Turquette <mturquette@...libre.com>,
        linux-kernel@...r.kernel.org, linux-rockchip@...ts.infradead.org,
        linux-clk@...r.kernel.org, linux-arm-kernel@...ts.infradead.org
Subject: Re: [PATCH] clk: rockchip: Slightly more accurate math in rockchip_mmc_get_phase()

Am Dienstag, 7. Mai 2019, 22:57:42 CEST schrieb Douglas Anderson:
> There's a bit of math in rockchip_mmc_get_phase() to calculate the
> "fine delay".  This math boils down to:
> 
>  PSECS_PER_SEC = 1000000000000.
>  ROCKCHIP_MMC_DELAY_ELEMENT_PSEC = 60
>  card_clk * ROCKCHIP_MMC_DELAY_ELEMENT_PSEC * 360 * x / PSECS_PER_SEC
> 
> ...but we do it in pieces to avoid overflowing 32-bits.  Right now we
> overdo it a little bit, though, and end up getting less accurate math
> than we could.  Right now we do:
> 
>  DIV_ROUND_CLOSEST((card_clk / 1000000) *
>                    (ROCKCHIP_MMC_DELAY_ELEMENT_PSEC / 10) *
>                    (360 / 10) *
> 		   delay_num,
> 		   PSECS_PER_SEC / 1000000 / 10 / 10)
> 
> This is non-ideal because:
> A) The pins on Rockchip SoCs are rated to go at most 150 MHz, so the
>    max card clock is 150 MHz.  Even ignoring this the maximum SD card
>    clock (for SDR104) would be 208 MHz.  This means you can decrease
>    your division by 100x and still not overflow:
>      hex(208000000 / 10000 * 6 * 36 * 0xff) == 0x44497200
> B) On many Rockchip SoCs we end up with a card clock that is actually
>    148500000 because we parent off the 297 MHz PLL.  That means the
>    math we're actually doing today is less than ideal.  Specifically:
>    148500000 / 1000000 = 148
> 
> Let's fix the math to be slightly more accurate.
> 
> NOTE: no known problems are fixed by this.  It was found simply by
> code inspection.  If you want to see the difference between the old
> and the new on a 148.5 MHz clock, this python can help:
> 
>   old = [x for x in
>          (int(round(148 * 6 * 36 * x / 10000.)) for x in range(256))
> 	 if x < 90]
>   new = [x for x in
>          (int(round(1485 * 6 * 36 * x / 100000.)) for x in range(256))
> 	 if x < 90]
> 
> The only differences are:
>   delay_num=17 54=>55
>   delay_num=22 70=>71
>   delay_num=27 86=>87
> 
> Signed-off-by: Douglas Anderson <dianders@...omium.org>

gave this a spin on multiple socs and all of them still detected a hs200-
card, so I've applied that for 5.3

Thanks
Heiko


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