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Message-ID: <1830378.zUSKOufHgj@phil>
Date: Thu, 09 May 2019 10:45:56 +0200
From: Heiko Stuebner <heiko@...ech.de>
To: Douglas Anderson <dianders@...omium.org>
Cc: Stephen Boyd <sboyd@...nel.org>,
Shawn Lin <shawn.lin@...k-chips.com>, hal@...emmerich.com,
amstan@...omium.org, Michael Turquette <mturquette@...libre.com>,
linux-kernel@...r.kernel.org, linux-rockchip@...ts.infradead.org,
linux-clk@...r.kernel.org, linux-arm-kernel@...ts.infradead.org
Subject: Re: [PATCH] clk: rockchip: Slightly more accurate math in rockchip_mmc_get_phase()
Am Dienstag, 7. Mai 2019, 22:57:42 CEST schrieb Douglas Anderson:
> There's a bit of math in rockchip_mmc_get_phase() to calculate the
> "fine delay". This math boils down to:
>
> PSECS_PER_SEC = 1000000000000.
> ROCKCHIP_MMC_DELAY_ELEMENT_PSEC = 60
> card_clk * ROCKCHIP_MMC_DELAY_ELEMENT_PSEC * 360 * x / PSECS_PER_SEC
>
> ...but we do it in pieces to avoid overflowing 32-bits. Right now we
> overdo it a little bit, though, and end up getting less accurate math
> than we could. Right now we do:
>
> DIV_ROUND_CLOSEST((card_clk / 1000000) *
> (ROCKCHIP_MMC_DELAY_ELEMENT_PSEC / 10) *
> (360 / 10) *
> delay_num,
> PSECS_PER_SEC / 1000000 / 10 / 10)
>
> This is non-ideal because:
> A) The pins on Rockchip SoCs are rated to go at most 150 MHz, so the
> max card clock is 150 MHz. Even ignoring this the maximum SD card
> clock (for SDR104) would be 208 MHz. This means you can decrease
> your division by 100x and still not overflow:
> hex(208000000 / 10000 * 6 * 36 * 0xff) == 0x44497200
> B) On many Rockchip SoCs we end up with a card clock that is actually
> 148500000 because we parent off the 297 MHz PLL. That means the
> math we're actually doing today is less than ideal. Specifically:
> 148500000 / 1000000 = 148
>
> Let's fix the math to be slightly more accurate.
>
> NOTE: no known problems are fixed by this. It was found simply by
> code inspection. If you want to see the difference between the old
> and the new on a 148.5 MHz clock, this python can help:
>
> old = [x for x in
> (int(round(148 * 6 * 36 * x / 10000.)) for x in range(256))
> if x < 90]
> new = [x for x in
> (int(round(1485 * 6 * 36 * x / 100000.)) for x in range(256))
> if x < 90]
>
> The only differences are:
> delay_num=17 54=>55
> delay_num=22 70=>71
> delay_num=27 86=>87
>
> Signed-off-by: Douglas Anderson <dianders@...omium.org>
gave this a spin on multiple socs and all of them still detected a hs200-
card, so I've applied that for 5.3
Thanks
Heiko
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