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Message-ID: <CALCETrVKMx+0E6y5-rJsaDD6Z0Kj_f6XWXprJxHVq+YR9zex3g@mail.gmail.com>
Date:   Sun, 9 Jun 2019 21:27:13 -0700
From:   Andy Lutomirski <luto@...nel.org>
To:     Fenghua Yu <fenghua.yu@...el.com>
Cc:     Andy Lutomirski <luto@...nel.org>,
        Thomas Gleixner <tglx@...utronix.de>,
        Ingo Molnar <mingo@...hat.com>, Borislav Petkov <bp@...en8.de>,
        H Peter Anvin <hpa@...or.com>,
        Ashok Raj <ashok.raj@...el.com>,
        Tony Luck <tony.luck@...el.com>,
        Ravi V Shankar <ravi.v.shankar@...el.com>,
        linux-kernel <linux-kernel@...r.kernel.org>, x86 <x86@...nel.org>
Subject: Re: [PATCH v4 2/5] x86/umwait: Initialize umwait control values

On Sun, Jun 9, 2019 at 9:23 PM Fenghua Yu <fenghua.yu@...el.com> wrote:
>
> On Sat, Jun 08, 2019 at 03:52:42PM -0700, Andy Lutomirski wrote:
> > On Fri, Jun 7, 2019 at 3:10 PM Fenghua Yu <fenghua.yu@...el.com> wrote:
> > >
> > > umwait or tpause allows processor to enter a light-weight
> > > power/performance optimized state (C0.1 state) or an improved
> > > power/performance optimized state (C0.2 state) for a period
> > > specified by the instruction or until the system time limit or until
> > > a store to the monitored address range in umwait.
> > >
> > > IA32_UMWAIT_CONTROL MSR register allows kernel to enable/disable C0.2
> > > on the processor and set maximum time the processor can reside in
> > > C0.1 or C0.2.
> > >
> > > By default C0.2 is enabled so the user wait instructions can enter the
> > > C0.2 state to save more power with slower wakeup time.
> >
> > Sounds good, but:
> >
> > > +#define MSR_IA32_UMWAIT_CONTROL_C02            BIT(0)
> >
> > > +static u32 umwait_control_cached = 100000;
> >
> > The code seems to disagree.
>
> The definition of bit[0] is: C0.2 is disabled when bit[0]=1. So
> 100000 means C0.2 is enabled (and max time is 100000).
>
> Would it be better to change
> +#define MSR_IA32_UMWAIT_CONTROL_C02            BIT(0)
> to
> +#define MSR_IA32_UMWAIT_CONTROL_C02_DISABLED            BIT(0)

Sounds like a good improvement.

Thanks,
Andy

> ?
>
> Thanks.
>
> -Fenghua

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