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Message-ID: <20190719162726.u5fi5k3tqove6hgn@brauner.io>
Date: Fri, 19 Jul 2019 18:27:28 +0200
From: Christian Brauner <christian@...uner.io>
To: Oleg Nesterov <oleg@...hat.com>
Cc: "Joel Fernandes (Google)" <joel@...lfernandes.org>,
linux-kernel@...r.kernel.org,
Suren Baghdasaryan <surenb@...gle.com>,
kernel-team@...roid.com, Andrea Arcangeli <aarcange@...hat.com>,
Andrew Morton <akpm@...ux-foundation.org>,
"Eric W. Biederman" <ebiederm@...ssion.com>,
Tejun Heo <tj@...nel.org>
Subject: Re: [PATCH RFC v1] pidfd: fix a race in setting exit_state for pidfd
polling
On Fri, Jul 19, 2019 at 06:14:05PM +0200, Oleg Nesterov wrote:
> it seems that I missed something else...
>
> On 07/17, Joel Fernandes (Google) wrote:
> >
> > @@ -1156,10 +1157,11 @@ static int wait_task_zombie(struct wait_opts *wo, struct task_struct *p)
> > ptrace_unlink(p);
> >
> > /* If parent wants a zombie, don't release it now */
> > - state = EXIT_ZOMBIE;
> > + p->exit_state = EXIT_ZOMBIE;
> > if (do_notify_parent(p, p->exit_signal))
> > - state = EXIT_DEAD;
> > - p->exit_state = state;
> > + p->exit_state = EXIT_DEAD;
> > +
> > + state = p->exit_state;
> > write_unlock_irq(&tasklist_lock);
>
> why do you think we also need to change wait_task_zombie() ?
>
> pidfd_poll() only needs the exit_state != 0 check, we know that it
> is not zero at this point. Why do we need to change exit_state before
> do_notify_parent() ?
Oh, because of?:
/*
* Move the task's state to DEAD/TRACE, only one thread can do this.
*/
state = (ptrace_reparented(p) && thread_group_leader(p)) ?
EXIT_TRACE : EXIT_DEAD;
if (cmpxchg(&p->exit_state, EXIT_ZOMBIE, state) != EXIT_ZOMBIE)
return 0;
So exit_state will definitely be set in this scenario. Good point.
Christian
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