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Message-ID: <20190807161359.GT2716@lahna.fi.intel.com>
Date: Wed, 7 Aug 2019 19:13:59 +0300
From: Mika Westerberg <mika.westerberg@...ux.intel.com>
To: David Laight <David.Laight@...lab.com>
Cc: 'Yehezkel Bernat' <yehezkelshb@...il.com>,
LKML <linux-kernel@...r.kernel.org>,
Andreas Noever <andreas.noever@...il.com>,
Michael Jamet <michael.jamet@...el.com>,
"Rafael J . Wysocki" <rjw@...ysocki.net>,
Len Brown <lenb@...nel.org>, Lukas Wunner <lukas@...ner.de>,
Mario Limonciello <Mario.Limonciello@...l.com>,
Anthony Wong <anthony.wong@...onical.com>,
"linux-acpi@...r.kernel.org" <linux-acpi@...r.kernel.org>
Subject: Re: [PATCH 3/8] thunderbolt: Use 32-bit writes when writing ring
producer/consumer
On Fri, Jul 05, 2019 at 04:04:19PM +0000, David Laight wrote:
> > Really a matter of taste, but maybe you want to consider having a single
> > function, with a 3rd parameter, bool is_tx.
> > The calls here will be unified to:
> > ring_iowrite(ring, ring->head, ring->is_tx);
> > (No condition is needed here).
> >
> > The implementation uses the new parameter to decide which part of the register
> > to mask, reducing the code duplication (in my eyes):
> >
> > val = ioread32(ring_desc_base(ring) + 8);
> > if (is_tx) {
> > val &= 0x0000ffff;
> > val |= value << 16;
> > } else {
> > val &= 0xffff0000;
> > val |= value;
> > }
> > iowrite32(val, ring_desc_base(ring) + 8);
> >
> > I'm not sure if it improves the readability or makes it worse. Your call.
>
> Gah, that is all horrid beyond belief.
> If a 32bit write is valid then the hardware must not be updating
> the other 16 bits.
> In which case the driver knows what they should be.
> So it can do a single 32bit write of the required value.
I'm not entirely sure I understand what you say above. Can you shed some
light on this by a concrete example how it should look like? :-)
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