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Message-ID: <20190829005009.GA5895@embeddedor>
Date: Wed, 28 Aug 2019 19:50:09 -0500
From: "Gustavo A. R. Silva" <gustavo@...eddedor.com>
To: Richard Weinberger <richard@....at>,
Artem Bityutskiy <dedekind1@...il.com>,
Adrian Hunter <adrian.hunter@...el.com>
Cc: linux-mtd@...ts.infradead.org, linux-kernel@...r.kernel.org,
"Gustavo A. R. Silva" <gustavo@...eddedor.com>
Subject: [PATCH] ubifs: super: Use struct_size() helper
One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct ubifs_znode {
...
struct ubifs_zbranch zbranch[];
};
Make use of the struct_size() helper instead of an open-coded version
in order to avoid any potential type mistakes.
So, replace the following form:
sizeof(struct ubifs_znode) + c->fanout * sizeof(struct ubifs_zbranch)
with:
struct_size(c->cnext, zbranch, c->fanout)
This code was detected with the help of Coccinelle.
Signed-off-by: Gustavo A. R. Silva <gustavo@...eddedor.com>
---
fs/ubifs/super.c | 3 +--
1 file changed, 1 insertion(+), 2 deletions(-)
diff --git a/fs/ubifs/super.c b/fs/ubifs/super.c
index 2706f13e3eb9..ca86489048c8 100644
--- a/fs/ubifs/super.c
+++ b/fs/ubifs/super.c
@@ -661,8 +661,7 @@ static int init_constants_sb(struct ubifs_info *c)
long long tmp64;
c->main_bytes = (long long)c->main_lebs * c->leb_size;
- c->max_znode_sz = sizeof(struct ubifs_znode) +
- c->fanout * sizeof(struct ubifs_zbranch);
+ c->max_znode_sz = struct_size(c->cnext, zbranch, c->fanout);
tmp = ubifs_idx_node_sz(c, 1);
c->ranges[UBIFS_IDX_NODE].min_len = tmp;
--
2.23.0
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