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Message-ID: <31cac0c1-98e4-c70e-e156-51a70813beff@arm.com>
Date: Wed, 2 Oct 2019 11:47:59 +0100
From: Valentin Schneider <valentin.schneider@....com>
To: Vincent Guittot <vincent.guittot@...aro.org>
Cc: linux-kernel <linux-kernel@...r.kernel.org>,
Ingo Molnar <mingo@...hat.com>,
Peter Zijlstra <peterz@...radead.org>,
Phil Auld <pauld@...hat.com>,
Srikar Dronamraju <srikar@...ux.vnet.ibm.com>,
Quentin Perret <quentin.perret@....com>,
Dietmar Eggemann <dietmar.eggemann@....com>,
Morten Rasmussen <Morten.Rasmussen@....com>,
Hillf Danton <hdanton@...a.com>
Subject: Re: [PATCH v3 04/10] sched/fair: rework load_balance
On 02/10/2019 09:30, Vincent Guittot wrote:
>> Isn't that one somewhat risky?
>>
>> Say both groups are classified group_has_spare and we do prefer_sibling.
>> We'd select busiest as the one with the maximum number of busy CPUs, but it
>> could be so that busiest.sum_h_nr_running < local.sum_h_nr_running (because
>> pinned tasks or wakeup failed to properly spread stuff).
>>
>> The thing should be unsigned so at least we save ourselves from right
>> shifting a negative value, but we still end up with a gygornous imbalance
>> (which we then store into env.imbalance which *is* signed... Urgh).
>
> so it's not clear what happen with a right shift on negative signed
> value and this seems to be compiler dependent so even
> max_t(long, 0, (local->idle_cpus - busiest->idle_cpus) >> 1) might be wrong
>
Yeah, right shift on signed negative values are implementation defined. This
is what I was worried about initially, but I think the expression resulting
from the subtraction is unsigned (both terms are unsigned) so this would
just wrap when busiest < local - but that is still a problem.
((local->idle_cpus - busiest->idle_cpus) >> 1) should be fine because we do
have this check in find_busiest_group() before heading off to
calculate_imbalance():
if (busiest->group_type != group_overloaded &&
(env->idle == CPU_NOT_IDLE ||
local->idle_cpus <= (busiest->idle_cpus + 1)))
/* ... */
goto out_balanced;
which ensures the subtraction will be at least 2. We're missing something
equivalent for the sum_h_nr_running case.
> I'm going to update it
>
>
>>
>> [...]
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